3. Determine the compound with formula C6H₁2O₂ that gives rise to the following spectra.IR2.5 2.6 2.7 2.8 2.9 384000 3800¹H NMR340036003200 3000764.524002800 2600220055V20001740cm-15.5Wavelength (um)48 (ppm)Peak Summary: 3.65 (s, 3H), 1.20 (s, 9H)8001600Wavenumber (cm)b. Redraw the structure and assign all of the ¹³C peaks.13C NMR: 174, 51, 40, 25140021200I101000012800

Double Bond Equivalence (DBE) for the molecular formula C6H12O2 calculated by using the following…

3. Determine the compound with formula C6H₁2O2 that gives rise to the following spectra. IR 25 26 27 28 29 3 % Transmittance www. WORE THE 3.5 HO 4000 3800 3600 3400 3200 3000 2800 2600 2400 2200 2000 1740 5.3 Wavelength (um) 500 In 1600 Wavenumber (cm) 7 1400 8 1200 9 10 1000 11 12

3. Determine the compound with formula C6H₁2O2 that gives rise to the following spectra. IR 25 26 27 28 29 3 % Transmittance www. WORE THE 3.5 HO 4000 3800 3600 3400 3200 3000 2800 2600 2400 2200 2000 1740 5.3 Wavelength (um) 500 In 1600 Wavenumber (cm) 7 1400 8 1200 9 10 1000 11 12

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

3. Determine the compound with formula C6H₁2O₂ that gives rise to the following spectra.
IR
2.5 2.6 2.7 2.8 2.9 3
8
4000 3800
¹H NMR
3400
3600
3200 3000
7
6
4.5
2400
2800 2600
2200
5
5
V
2000
1740
cm-1
5.5
Wavelength (um)
4
8 (ppm)
Peak Summary: 3.65 (s, 3H), 1.20 (s, 9H)
800
1600
Wavenumber (cm)
b. Redraw the structure and assign all of the ¹³C peaks.
13C NMR: 174, 51, 40, 25
1400
2
1200
I
10
1000
0
12
800

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