3. Determine m < 0 10 24 17 B.

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Problem 3: Determine \( m \angle \theta \)**

In the given problem, we have a triangle \( \triangle ABC \) with the following side lengths:
- \( AB = 24 \)
- \( AC = 10 \)
- \( BC = 17 \)

The task is to find the measure of angle \( \theta \), which is located at vertex \( C \).

To find \( \theta \), we can use the Law of Cosines. The Law of Cosines states that for any triangle with sides \( a \), \( b \), and \( c \), and the angle \( \gamma \) opposite side \( c \), the relationship is given by:

\[ c^2 = a^2 + b^2 - 2ab \cos(\gamma) \]

In this context:
- \( a = 24 \)
- \( b = 10 \)
- \( c = 17 \)
- \( \gamma = \theta \)

Applying the Law of Cosines:

\[ 17^2 = 24^2 + 10^2 - 2 \times 24 \times 10 \times \cos(\theta) \]

Simplify this equation step-by-step to solve for \( \cos(\theta) \), and then use the inverse cosine function to find \( \theta \).

Here is the step-by-step simplification:
\[ 289 = 576 + 100 - 480 \cos(\theta) \]
\[ 289 = 676 - 480 \cos(\theta) \]
\[ 289 - 676 = -480 \cos(\theta) \]
\[ -387 = -480 \cos(\theta) \]
\[ \cos(\theta) = \frac{387}{480} \]
\[ \cos(\theta) \approx 0.80625 \]

Now, use the inverse cosine (arccos) function to find \( \theta \):
\[ \theta \approx \cos^{-1}(0.80625) \]

Using a calculator,
\[ \theta \approx 36.87^\circ \]

Therefore, the measure \( m \angle \theta \approx 36.87^\circ \).
Transcribed Image Text:**Problem 3: Determine \( m \angle \theta \)** In the given problem, we have a triangle \( \triangle ABC \) with the following side lengths: - \( AB = 24 \) - \( AC = 10 \) - \( BC = 17 \) The task is to find the measure of angle \( \theta \), which is located at vertex \( C \). To find \( \theta \), we can use the Law of Cosines. The Law of Cosines states that for any triangle with sides \( a \), \( b \), and \( c \), and the angle \( \gamma \) opposite side \( c \), the relationship is given by: \[ c^2 = a^2 + b^2 - 2ab \cos(\gamma) \] In this context: - \( a = 24 \) - \( b = 10 \) - \( c = 17 \) - \( \gamma = \theta \) Applying the Law of Cosines: \[ 17^2 = 24^2 + 10^2 - 2 \times 24 \times 10 \times \cos(\theta) \] Simplify this equation step-by-step to solve for \( \cos(\theta) \), and then use the inverse cosine function to find \( \theta \). Here is the step-by-step simplification: \[ 289 = 576 + 100 - 480 \cos(\theta) \] \[ 289 = 676 - 480 \cos(\theta) \] \[ 289 - 676 = -480 \cos(\theta) \] \[ -387 = -480 \cos(\theta) \] \[ \cos(\theta) = \frac{387}{480} \] \[ \cos(\theta) \approx 0.80625 \] Now, use the inverse cosine (arccos) function to find \( \theta \): \[ \theta \approx \cos^{-1}(0.80625) \] Using a calculator, \[ \theta \approx 36.87^\circ \] Therefore, the measure \( m \angle \theta \approx 36.87^\circ \).
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