3. Compute the factor of safety against a bearing capacity failure for the 3 m square concrete footing shown below. The groundwater table is 2.5 m below the ground surface. Use Vesic's bearing capacity formula. [Course Objective #2] 3a. Intermediate calculation - enter the applied bearing pressure (q) in kPa. 3b. Intermediate calculation - enter the ultimate bearing capacity (quit) in kPa. 3c. Final calculation - enter the factor of safety. 2.5 m 0.75 m P = 6025 KN 3 m SW, y≈ 18 kN/m³ c' = 0 kPa $' = 36° SM, y≈ 18.5 kN/m³ c' = 3 kPa $' = 30°
3. Compute the factor of safety against a bearing capacity failure for the 3 m square concrete footing shown below. The groundwater table is 2.5 m below the ground surface. Use Vesic's bearing capacity formula. [Course Objective #2] 3a. Intermediate calculation - enter the applied bearing pressure (q) in kPa. 3b. Intermediate calculation - enter the ultimate bearing capacity (quit) in kPa. 3c. Final calculation - enter the factor of safety. 2.5 m 0.75 m P = 6025 KN 3 m SW, y≈ 18 kN/m³ c' = 0 kPa $' = 36° SM, y≈ 18.5 kN/m³ c' = 3 kPa $' = 30°
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![### Problem Statement:
**Objective:**
Compute the factor of safety against a bearing capacity failure for the 3 m square concrete footing shown below. The groundwater table is 2.5 m below the ground surface. Use Vesic’s bearing capacity formula. [Course Objective #2]
**Calculations Required:**
- **3a.** Intermediate calculation - Enter the applied bearing pressure (\(q\)) in kPa.
- **3b.** Intermediate calculation - Enter the ultimate bearing capacity (\(q_{ult}\)) in kPa.
- **3c.** Final calculation - Enter the factor of safety.
### Diagram Explanation:
- **Structure:**
- A footing with a width of 3 m supports a load (\(P\)) of 6025 kN.
- The footing is embedded 0.75 m below the ground surface.
- **Ground Conditions:**
- Above the groundwater table: Soil type (SW) with characteristics:
- Unit weight (\(\gamma\)) ≈ 18 kN/m³
- Cohesion (\(c'\)) = 0 kPa
- Friction angle (\(\phi'\)) = 36°
- Below the groundwater table: Soil type (SM) with characteristics:
- Unit weight (\(\gamma\)) ≈ 18.5 kN/m³
- Cohesion (\(c'\)) = 3 kPa
- Friction angle (\(\phi'\)) = 30°
- **Groundwater Table:**
- Positioned 2.5 m below the ground surface.
### Task Overview:
Calculate bearing pressures and safety factor using the given soil parameters and load information. Apply Vesic’s bearing capacity formula to determine the required values step-by-step.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F669cd848-f6cb-4d2d-b698-085712d01b58%2Fc74c122a-6ecc-4ce4-ba23-21a2696b1bbc%2Fa97cxzd_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement:
**Objective:**
Compute the factor of safety against a bearing capacity failure for the 3 m square concrete footing shown below. The groundwater table is 2.5 m below the ground surface. Use Vesic’s bearing capacity formula. [Course Objective #2]
**Calculations Required:**
- **3a.** Intermediate calculation - Enter the applied bearing pressure (\(q\)) in kPa.
- **3b.** Intermediate calculation - Enter the ultimate bearing capacity (\(q_{ult}\)) in kPa.
- **3c.** Final calculation - Enter the factor of safety.
### Diagram Explanation:
- **Structure:**
- A footing with a width of 3 m supports a load (\(P\)) of 6025 kN.
- The footing is embedded 0.75 m below the ground surface.
- **Ground Conditions:**
- Above the groundwater table: Soil type (SW) with characteristics:
- Unit weight (\(\gamma\)) ≈ 18 kN/m³
- Cohesion (\(c'\)) = 0 kPa
- Friction angle (\(\phi'\)) = 36°
- Below the groundwater table: Soil type (SM) with characteristics:
- Unit weight (\(\gamma\)) ≈ 18.5 kN/m³
- Cohesion (\(c'\)) = 3 kPa
- Friction angle (\(\phi'\)) = 30°
- **Groundwater Table:**
- Positioned 2.5 m below the ground surface.
### Task Overview:
Calculate bearing pressures and safety factor using the given soil parameters and load information. Apply Vesic’s bearing capacity formula to determine the required values step-by-step.
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