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- A hiker walks 3.00 km north and then 4.00 km west, all in one hour and forty minutes, (a) Calculate his average speed in km/h. (b) Calculate the magnitude of his average velocity. (See Section 3.2 and 3.3.)A car is traveling east at 25.0 m/s when it turns north and accelerates to 35.0 m/s, all during a time of 6.00 s. Calculate the magnitude of the car's average acceleration. (See Section 3.3.)Find the following for path B in Figure 2.59: (a) The distance traveled. (b) The magnitude of the displacement from start to finish. (c) The displacement from start to finish.
- 1. Where and when will they meet? What assumption did you make? Draw a graphical representation to approximate the solution. Displacement vs Time Person B Person A 200 150 100 v = 8.00 m/s v = 7.00 m/s 50 d = 200.0 m 25 10 15 20 5 Time (s) Distance (m)0. Which is the most accurate plot of velocity versus time for the braking car? a. Velocity v. Time Graph for the Braking Car с. Velocity v. Time Graph for the Braking Car 30 30 25 25 20 20 15 15 10 10 5. 0.5 1 1.5 2 2.5 3 3.5 4 4.5 0. 0.5 1 1.5 2 Time (s) 2.5 3 3.5 4 4.5 Time (min) Velocity v. Time Graph for the Braking Car b. d. Velocity v. Time Graph for the Braking Car 30 30 25 25 20 20 15 15 10 10 5. 0. 0.5 1 1.5 2 2.5 3 3.5 4 4.5 0. 0.5 1 1.5 2 2.5 3 3.5 4 4.5 Time (s) Time (s) Velocity (m/s) Velocity (m/s) Velocity (m/s) Velocity (m/s)6. A car starts from rest and accelerates at a rate of 1.8 m/s² West for 15s. It goes at a constant velocity for 50s and then accelerates at a rate of 2.1m/s² East for 10 s. Use West as the positive direction. a. Draw an acceleration graph for this situation. Remember to quantitatively label your axes. a (m/812) t(s) 0-15 15-65 65-75 b. What is the change in velocity for each time interval? Av (m/s) t(s) Draw a velocity graph for this situation. Remember to quantitatively label your axes. v (m/s) E t(s) d. What is the total displacement between t-Os and t= 75 s?
- 1. UST Eco-Tiger vehicle climbed to a hill which is defined by the equation, x2 = 625(16 –- y). If the vehicle moves from point A with a speed of 20 m/s and starts to speed up at constant rate for exactly 4.72136 seconds until it reaches point B. Determine the magnitude of the x2 = 625(16 - y) 15m vehicle's acceleration when the distance from A and B is 100 meters.A velocity time graph for a moving object is shown below. v (m/s) 7 6 5- 4 3+ 2+ 1 1 2 3 - 4 +5 6 7 Find the acceleration (in units of m/s2) of the object at t = 4s. O a. -1.5 O b. +1.5 O c. 0 O d. Cannot be determined from the given graph. ➜t(s)2. A car is driven 1200 m north at 20.0 m/s and then driven 1600 m east at 25.0 m/s. What is the magnitude of the average velocity for this trip? a) 16.1 m/s b) 22.6 m/s c) 31.3 m/s d) 11.3 m/s e) 62.2 m/s
- 4. A car accelerates on a straight road from rest to 88 km/h in 6.5 s. What is the magnitude of its average acceleration? Your final units should be m/s.3. Shown below is the acceleration function for a particle over the approximately first two seconds of its motion. Draw an approximate graph of velocity as a function of time assuming v, = 0 m/s. alt) t 20 15 10 5. 0.5 1.0 1.5 2.0 2.5 4. Let vector A point from the origin into the first quadrant of the xy plane and vector B point from the origin into the third quadrant. The vector Ă – B must be in which quadrant?1. Vave. In 1.00 [min], James moved 30.0 [m], 30.9° South of East from his initial position. What is James' average velocity? A. v = 0.429 [m/s]î + 0.257 [m/s]j B. v = 0.429 [m/s]î – 0.257 [m/s] j C. v = 0.257 [m/s]i+ 0.429 [m/s]j D. v = 0.257 [m/s]î – 0.429 [m/s]j