3. Buffers a) In choosing a buffer, it is necessary to select a weak acid that has a pKa near the target pH. Calculate the pka of each reaction below. Which one should be used to make a buffer at pH = 10.0.
3. Buffers a) In choosing a buffer, it is necessary to select a weak acid that has a pKa near the target pH. Calculate the pka of each reaction below. Which one should be used to make a buffer at pH = 10.0.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3
![3. Buffers
a)
In choosing a buffer, it is necessary to select a weak acid that has a pka near the
target pH. Calculate the pK, of each reaction below. Which one should be used to make a
buffer at pH= 10.0.
H₂CO3HCO3 + H+
HCO3 CO3² + H+
H3PO4→ H₂PO4 + H+
H₂PO4 →HPO4² + H+
HPO4²PO4³ + H+
Ka = 4.2 x 10-7
Ka 4.8 x 10-11
Ka = 7.5 x 10-³3
Ka = 6.2 x 10-8
Ka = 4.8 x 10-13
(available salts: NaHCO3)
(available salts: NaHCO3/Na2CO3)
(available salts: NaH₂PO4)
(available salts: Na₂HPO4)
(available salts: Na2HPO4, Na3PO4)
b)
Using the Henderson-Hasselbalch equation, calculate the concentration of the
conjugate base using 0.10 M weak acid.
pH = pKa + log (
[conjugate base]
[weak acid]
c)
Using the buffer system that you selected in a) calculate the mass (in grams) of
the conjugate base and weak acid needed to make 100 mL of the buffer.
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8713e9b-73ac-4e4f-a322-df330d573c40%2Fb90de093-869f-4c2d-b184-2c34f3fa347b%2F4y88egd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Buffers
a)
In choosing a buffer, it is necessary to select a weak acid that has a pka near the
target pH. Calculate the pK, of each reaction below. Which one should be used to make a
buffer at pH= 10.0.
H₂CO3HCO3 + H+
HCO3 CO3² + H+
H3PO4→ H₂PO4 + H+
H₂PO4 →HPO4² + H+
HPO4²PO4³ + H+
Ka = 4.2 x 10-7
Ka 4.8 x 10-11
Ka = 7.5 x 10-³3
Ka = 6.2 x 10-8
Ka = 4.8 x 10-13
(available salts: NaHCO3)
(available salts: NaHCO3/Na2CO3)
(available salts: NaH₂PO4)
(available salts: Na₂HPO4)
(available salts: Na2HPO4, Na3PO4)
b)
Using the Henderson-Hasselbalch equation, calculate the concentration of the
conjugate base using 0.10 M weak acid.
pH = pKa + log (
[conjugate base]
[weak acid]
c)
Using the buffer system that you selected in a) calculate the mass (in grams) of
the conjugate base and weak acid needed to make 100 mL of the buffer.
4
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