3. An influenza virus is spreading according to the function P(t) = 50(2) Where P is the number of people infected after t days a. How fast is the virus spreading after 1 week? b. Assuming exponential growth continues, after how many days is the spread of the virus accelerating by 1500 people/day per day?
3. An influenza virus is spreading according to the function P(t) = 50(2) Where P is the number of people infected after t days a. How fast is the virus spreading after 1 week? b. Assuming exponential growth continues, after how many days is the spread of the virus accelerating by 1500 people/day per day?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Transcribed Image Text:3. An influenza virus is spreading according to the function P(t) = 50(2)
Where P is the number of people infected after t days
a. How fast is the virus spreading after 1 week?
b. Assuming exponential growth continues, after how many days is the spread of the
virus accelerating by 1500 people/day per day?
![3.0 when € =]
PO) = 50€
7A
3.5
= 50₂ ~$656
b. when P = 1500
50e
$
e ² = 1500÷50 = 30
2
= 1500
2 = In 30
t=21n 30 = 6.8 day
= 6.8 days
1. Assuming that exponential growth continues, it would take 6.8
of the virus to accelerate by 1500
for the spread
days for the
spreading
people / day per day.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83a66ebf-8df2-4cca-a221-2056e657c82d%2Fcfd4b070-8379-4bbe-9d64-817b611141f0%2Ft71bhgc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.0 when € =]
PO) = 50€
7A
3.5
= 50₂ ~$656
b. when P = 1500
50e
$
e ² = 1500÷50 = 30
2
= 1500
2 = In 30
t=21n 30 = 6.8 day
= 6.8 days
1. Assuming that exponential growth continues, it would take 6.8
of the virus to accelerate by 1500
for the spread
days for the
spreading
people / day per day.
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