3. An individual who has automobile insurance from a certain company is ran- domly selected. Let Y be the number of moving violations for which the individual was cited during the last 3 years. The pmf of Y is 1 2 p(y) | .60 .25 .10 .05 3 What is the variance of Y? А. 1.1 В. .60 C. .79 D. 1 E. None of the above 4. Based on the pmf in problem 3, what is the probability that an individual was cited between 1 and 3 times (inclusive)? А. .25 В. .05 С. .30 D. .40 E. None of the above

MATLAB: An Introduction with Applications
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3.
An individual who has automobile insurance from a certain company is ran-
domly selected. Let Y be the number of moving violations for which the individual was
cited during the last 3 years. The pmf of Y is
1
p(y) | .60
.25
.10
.05
What is the variance of Y?
Α. 1.1
В. .60
C. .79
D. 1
E. None of the above
4.
Based on the pmf in problem 3, what is the probability that an individual
was cited between 1 and 3 times (inclusive)?
A. .25
В. .05
С. .30
D. .40
E. None of the above
Transcribed Image Text:3. An individual who has automobile insurance from a certain company is ran- domly selected. Let Y be the number of moving violations for which the individual was cited during the last 3 years. The pmf of Y is 1 p(y) | .60 .25 .10 .05 What is the variance of Y? Α. 1.1 В. .60 C. .79 D. 1 E. None of the above 4. Based on the pmf in problem 3, what is the probability that an individual was cited between 1 and 3 times (inclusive)? A. .25 В. .05 С. .30 D. .40 E. None of the above
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