3. An equation for the graph shown to the right is: a. y = x²(x-3) b. y = x(x − 3)³ c. y = x²(x-3)³ d. y=x2(x-3)3 8 4. The graph of the function y = x² is transformed to the graph of the function y = −[2(x+3)] 4 + 1 by: a. a vertical stretch by a factor of 2, a reflection in the x-axis, a translation of 3 units to the right, and a translation of 1 unit up b. a horizontal stretch by a factor of 2, a reflection in the x-axis, a translation of 3 C. units to the right, and a translation of 1 unit up 1 a horizontal compression by a factor of ½, a reflection in the x-axis, a translation of 3 units to the left, and a translation of 1 unit up d. a horizontal compression by a factor of the right, and a translation of 1 unit up 1 a reflection in the x-axis, a translation of 3 units to 4

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter9: Quadratic Equations And Functions
Section9.6: Graph Quadratic Functions Using Properties
Problem 9.97TI: Graph f(x)=x22x+3 by using its properties.
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3. An equation for the graph shown to the right is:
a. y = x²(x-3)
b. y = x(x − 3)³
c. y = x²(x-3)³
d. y=x2(x-3)3
8
4. The graph of the function y = x² is transformed to the graph of the function
y = −[2(x+3)] 4 + 1 by:
a.
a vertical stretch by a factor of 2, a reflection in the x-axis, a translation of 3 units
to the right, and a translation of 1 unit up
b. a horizontal stretch by a factor of 2, a reflection in the x-axis, a translation of 3
C.
units to the right, and a translation of 1 unit up
1
a horizontal compression by a factor of ½, a reflection in the x-axis, a translation of 3 units to
the left, and a translation of 1 unit up
d. a horizontal compression by a factor of
the right, and a translation of 1 unit up
1
a reflection in the x-axis, a translation of 3 units to
4
Transcribed Image Text:3. An equation for the graph shown to the right is: a. y = x²(x-3) b. y = x(x − 3)³ c. y = x²(x-3)³ d. y=x2(x-3)3 8 4. The graph of the function y = x² is transformed to the graph of the function y = −[2(x+3)] 4 + 1 by: a. a vertical stretch by a factor of 2, a reflection in the x-axis, a translation of 3 units to the right, and a translation of 1 unit up b. a horizontal stretch by a factor of 2, a reflection in the x-axis, a translation of 3 C. units to the right, and a translation of 1 unit up 1 a horizontal compression by a factor of ½, a reflection in the x-axis, a translation of 3 units to the left, and a translation of 1 unit up d. a horizontal compression by a factor of the right, and a translation of 1 unit up 1 a reflection in the x-axis, a translation of 3 units to 4
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