3.) An electron experiences the greatest force as it travels 2.8 x 10^6 m/s in a magnetic field when it is moving northward. The force is vertically upward and of magnitude 6.2 x 10^-13 N. What is the magnitude and direction of the magnetic field?
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- 3) A long straight wire carries a current of 1.3 A. An electron is 2.3 cm from the wire and initially moving at speed 7.2 x 106 m/s in the opposite direction as the current in the wire. a) The electron is moving in the magnetic field from the wire. Calculate the magnitude of the magnetic force on the electron. b) Which of the following correctly describes the direction of the magnetic force on the electron? A) The magnetic force on the electron is directed toward the wire B) The magnetic force on the electron is directed away from the wire1. An electron moves west at 6.9 x 105 m/s through a magnetic field directed [W75°N] with strength of 1.3 x 102 T. What magnitude and direction would the electron experience a magnetic force?1. An electron has a velocity v = (2 x 106 m/s) i +(3.0x 106 m/s)j moves through a uniform magnetic field B = (0.030 T) ? - (0.15 T)j. (a) Find the force on the electron due to the magnetic field. (b) mass of electron is 9.11 x 10-31 kg what will be the radius of the circular path for the electron in the magnetic field?
- 1. A proton has velocity v = (40,000 i +30,000 j) m/s as it enters a uniform magnetic field B-70 µT 1. What are (a) the radius of the helical path taken by the proton and (b) the pitch of that path? (c) To an observer looking into the magnetic field region from the entrance point of the proton, does the proton spiral clockwise or counterclockwise as it moves?A proton travels with a speed of 4.90 x 106 m/s at an angle of 62° with the direction of a magnetic field of magnitude 0.240 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? N (b) What is the proton's acceleration? m/s²4. Please refer again to the diagram. This time we have a charge of 3.86 x 10^-6 C moving at velocity 7.00 x 10^5 m/s through a magnetic field of strength 1.28 T and an electric field of strength 8.92 x 10^5 N/C. What is the magnitude of the total force on this charge? 0.02 N 0.01 N 0.03 N 0.03 N
- ements valuación An electron moves in a uniform circular motion under the action of an external magnetic field perpendicular to the circular path. Consider that the charge and mass of the electron are respectively q = 1.6 x 10-¹⁹ C, m = 9.11 10-31 Kg, the velocity of the electron is v = = 2.8 × 107 and the magnitude of the external magnetic field is B = 2.1 x 10-³T. Calculate the radius R of the circle formed by the electron in its path during its displacement and choose the correct option. 5.5 cm O 7.5 cm 9.5 cm O 3.5 cm 1 pts Question 3Part 2) A proton moving with a speed 3.84 × 10° m/s through a 2.99 T magnetic field experiences a force of magnitude 1.59 x 10-12 N. (Mass of the proton = 1.673 × 10¬27 kg, charge 1.602 × 10-19 C). What is the angle between the proton's velocity and the magnetic field? Part 3) What is the proton's acceleration? a = m/s?29. At an instant in time, an electron has velocity, v = 100i - 300j + 200k km/s while it is in a magnetic field, B = 2i - 3j + 4k T. Find the acceleration of the electron at this instant. Use the vector table below to show any important vectors. Show only numerical results in the table. (m = 9.109 X 10" kg, q = -i.6 X 10'1º C) Vector i k