3. An amoeba may have 1.0 x1016 protons and a net charge of +0.30 pC (1 pC = 10-12 C). A. How many electrons is this amoeba missing? B. Protons and electrons tend to pair up (because of Coloumb's Law). However, some protons are missing electrons here. What fraction of all the protons are missing electrons?

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**Question 3: Charge and Protons in an Amoeba**

An amoeba may have \( 1.0 \times 10^{16} \) protons and a net charge of \( +0.30 \) pC (1 pC = \( 10^{-12} \) C).

![Amoeba Image]

**A. How many electrons is this amoeba missing?**

**B. Protons and electrons tend to pair up (because of Coulomb's Law). However, some protons are missing electrons here. What fraction of all the protons are missing electrons?**

---

**Graphical Description:**
There is an image of an amoeba shown in the question. The amoeba appears irregular in shape with various internal structures visible, likely representing its organelles. This serves as a visual aid to familiarize students with what an amoeba looks like in a microscopic image.

---

**Calculation Details for Educational Context:**

1. **Calculating the Charge in Coulombs:**
   Given net charge \( Q \) is \( +0.30 \) pC or \( 0.30 \times 10^{-12} \) C.

2. **Determining Number of Missing Electrons:**
   The charge of a single electron (\( e \)) is approximately \( -1.602 \times 10^{-19} \) C.

   Missing electrons \( n \) can be calculated by
   \[
   Q = n \times e.
   \]
   Therefore,
   \[
   n = \frac{Q}{e} = \frac{0.30 \times 10^{-12}}{1.602 \times 10^{-19}} \approx 1.87 \times 10^{6}.
   \]
   So, the amoeba is missing approximately \( 1.87 \times 10^{6} \) electrons.

3. **Fraction of Protons Missing Electrons:**
   Given \( 1.0 \times 10^{16} \) protons,
   \[
   \text{Fraction} = \frac{\text{Missing Electrons}}{\text{Total Protons}} = \frac{ 1.87 \times 10^{6} }{ 1.0 \times 10^{16} } = 1.87 \times 10^{-10}.
   \]
   Therefore, the fraction of all the pro
Transcribed Image Text:**Question 3: Charge and Protons in an Amoeba** An amoeba may have \( 1.0 \times 10^{16} \) protons and a net charge of \( +0.30 \) pC (1 pC = \( 10^{-12} \) C). ![Amoeba Image] **A. How many electrons is this amoeba missing?** **B. Protons and electrons tend to pair up (because of Coulomb's Law). However, some protons are missing electrons here. What fraction of all the protons are missing electrons?** --- **Graphical Description:** There is an image of an amoeba shown in the question. The amoeba appears irregular in shape with various internal structures visible, likely representing its organelles. This serves as a visual aid to familiarize students with what an amoeba looks like in a microscopic image. --- **Calculation Details for Educational Context:** 1. **Calculating the Charge in Coulombs:** Given net charge \( Q \) is \( +0.30 \) pC or \( 0.30 \times 10^{-12} \) C. 2. **Determining Number of Missing Electrons:** The charge of a single electron (\( e \)) is approximately \( -1.602 \times 10^{-19} \) C. Missing electrons \( n \) can be calculated by \[ Q = n \times e. \] Therefore, \[ n = \frac{Q}{e} = \frac{0.30 \times 10^{-12}}{1.602 \times 10^{-19}} \approx 1.87 \times 10^{6}. \] So, the amoeba is missing approximately \( 1.87 \times 10^{6} \) electrons. 3. **Fraction of Protons Missing Electrons:** Given \( 1.0 \times 10^{16} \) protons, \[ \text{Fraction} = \frac{\text{Missing Electrons}}{\text{Total Protons}} = \frac{ 1.87 \times 10^{6} }{ 1.0 \times 10^{16} } = 1.87 \times 10^{-10}. \] Therefore, the fraction of all the pro
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