3. A thin rod is free to rotate without friction about a fixed axis at Point A. The other end (Point B) is attached to a (massless) cable at an angle of 45° relative to the rod. a. Initially the rod is being held stationary in a horizontal position. What is the force, F, in the cable? What are the forces that the support is putting on the rod at Point A? A Thin Rod m= 18 kg L=3m F W1 = 0 α1 = 0 α₂ = ? F₁ = ? b. The force, F, is suddenly changed to 200 N. What is the angular acceleration of the rod just after the force is changed? What are the forces that the support is putting on the rod at Point A now? Thin Rod m= 18 kg L=3m 45° F₂ = 200 N 45° B W₂ = 0 B

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Chapter12: Static Equilibrium And Elasticity
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Problem 12.52AP
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3. A thin rod is free to rotate without friction about a fixed axis at Point A. The other end
(Point B) is attached to a (massless) cable at an angle of 45° relative to the rod.
a. Initially the rod is being held stationary in a horizontal position. What is the force, F, in
the cable? What are the forces that the support is putting on the rod at Point A?
Thin Rod
m= 18 kg
L=3m
W₁ = 0
α1 = 0
Thin Rod
m= 18 kg
L=3m
F₁ = ?
a₂ = ?
45°
b. The force, F, is suddenly changed to 200 N. What is the angular acceleration of the rod
just after the force is changed? What are the forces that the support is putting on the
rod at Point A now?
= 200 N
45°
B
W₂ = 0
B
Transcribed Image Text:3. A thin rod is free to rotate without friction about a fixed axis at Point A. The other end (Point B) is attached to a (massless) cable at an angle of 45° relative to the rod. a. Initially the rod is being held stationary in a horizontal position. What is the force, F, in the cable? What are the forces that the support is putting on the rod at Point A? Thin Rod m= 18 kg L=3m W₁ = 0 α1 = 0 Thin Rod m= 18 kg L=3m F₁ = ? a₂ = ? 45° b. The force, F, is suddenly changed to 200 N. What is the angular acceleration of the rod just after the force is changed? What are the forces that the support is putting on the rod at Point A now? = 200 N 45° B W₂ = 0 B
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