3. A speeding car going 30 m/s passes a police car that is at rest. At the moment the speeder passes, the police car pulls out and accelerates 4 m/s/s. The speeder continues going 30 m/s. Which is ahead and by how much after 10 seconds? When does the police car catch the speeder?

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3. A speeding car going 30 m/s passes a police car that is at rest. At the moment the speeder
passes, the police car pulls out and accelerates 4 m/s/s. The speeder continues going 30 m/s.
Which is ahead and by how much after 10 seconds? When does the police car catch the
speeder?
Transcribed Image Text:3. A speeding car going 30 m/s passes a police car that is at rest. At the moment the speeder passes, the police car pulls out and accelerates 4 m/s/s. The speeder continues going 30 m/s. Which is ahead and by how much after 10 seconds? When does the police car catch the speeder?
Expert Solution
Step 1

The speeder will be ahead by 300 m after 10 seconds. The police car will catch the speeder after 25 seconds, when both vehicles will be moving at the same speed of 30 m/s.

The position of the speeder at time t (in seconds) can be calculated as: x = 30 * t

The position of the police car at time t can be calculated as: x = 0.5 * 4 * t2 + 0

 

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