3. A passenger train is traveling at 25.0 m/s on a straight track when the engineer spots a freight train, whose caboose (last car) is 200 m ahead on the same track. The freight train is traveling at 15.0 m/s in the same direction as the passenger train. Worried about a collision with the slower train, the engineer of the passenger train immediately hits the brakes, causing a constant acceleration of 0.100 m/s² in the direction opposite the train's velocity. Meanwhile, the freight train continues with constant speed. In this problem, we will work out whether the two trains will collide.

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Chapter1: Units, Trigonometry. And Vectors
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3. A passenger train is traveling at 25.0 m/s on a straight track when the engineer spots a freight train, whose
caboose (last car) is 200 m ahead on the same track. The freight train is traveling at 15.0 m/s in the same
direction as the passenger train. Worried about a collision with the slower train, the engineer of the passenger
train immediately hits the brakes, causing a constant acceleration of 0.100 m/s² in the direction opposite the
train's velocity. Meanwhile, the freight train continues with constant speed. In this problem, we will work out
whether the two trains will collide.
on, inc
UPT = 25.0 m/s
a = -0.100 m/s²
200 m
UFT = 15.0 m/s
Take x = 0 to be the position of the front of the passenger train at the moment the engineer first applies the
brakes. If the train had not braked, its position as a function of time would be given by
xp(t) = (25.0 m/s)t.
But because it is braking, a correct equation must take its acceleration into account.
CONTINUED ON NEXT PAGE
(1)
a) Write an equation for the passenger train's (front end) position as a function of time, xp(t), that correctly
includes its acceleration. Also write an equation for the freight train's (back end) position as a function of time,
xF(t).
b) Use your equations from part (a) to determine whether the two trains will ever collide, and find the location
of the collision if there is one. (Hint: what must be true about the positions of the trains if they collide? Are
there any times at which this occurs?)
Transcribed Image Text:3. A passenger train is traveling at 25.0 m/s on a straight track when the engineer spots a freight train, whose caboose (last car) is 200 m ahead on the same track. The freight train is traveling at 15.0 m/s in the same direction as the passenger train. Worried about a collision with the slower train, the engineer of the passenger train immediately hits the brakes, causing a constant acceleration of 0.100 m/s² in the direction opposite the train's velocity. Meanwhile, the freight train continues with constant speed. In this problem, we will work out whether the two trains will collide. on, inc UPT = 25.0 m/s a = -0.100 m/s² 200 m UFT = 15.0 m/s Take x = 0 to be the position of the front of the passenger train at the moment the engineer first applies the brakes. If the train had not braked, its position as a function of time would be given by xp(t) = (25.0 m/s)t. But because it is braking, a correct equation must take its acceleration into account. CONTINUED ON NEXT PAGE (1) a) Write an equation for the passenger train's (front end) position as a function of time, xp(t), that correctly includes its acceleration. Also write an equation for the freight train's (back end) position as a function of time, xF(t). b) Use your equations from part (a) to determine whether the two trains will ever collide, and find the location of the collision if there is one. (Hint: what must be true about the positions of the trains if they collide? Are there any times at which this occurs?)
c) On the axes below, sketch and label graphs of a vs. t for the two trains. Comment on how the graphs
relate to your results in part (b).
X
Transcribed Image Text:c) On the axes below, sketch and label graphs of a vs. t for the two trains. Comment on how the graphs relate to your results in part (b). X
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