Please show work 3. A passenger train is traveling at 25.0 m/s on a straight track when the engineer spots a freight train, whosecaboose (last car) is 200 m ahead on the same track. The freight train is traveling at 15.0 m/s in the samedirection as the passenger train. Worried about a collision with the slower train, the engineer of the passengertrain immediately hits the brakes, causing a constant acceleration of 0.100 m/s² in the direction opposite thetrain's velocity. Meanwhile, the freight train continues with constant speed. In this problem, we will work outwhether the two trains will collide.on, incUPT = 25.0 m/sa = -0.100 m/s²200 mUFT = 15.0 m/sTake x = 0 to be the position of the front of the passenger train at the moment the engineer first applies thebrakes. If the train had not braked, its position as a function of time would be given byxp(t) = (25.0 m/s)t.But because it is braking, a correct equation must take its acceleration into account.CONTINUED ON NEXT PAGE(1)a) Write an equation for the passenger train's (front end) position as a function of time, xp(t), that correctlyincludes its acceleration. Also write an equation for the freight train's (back end) position as a function of time,xF(t).b) Use your equations from part (a) to determine whether the two trains will ever collide, and find the locationof the collision if there is one. (Hint: what must be true about the positions of the trains if they collide? Arethere any times at which this occurs?) c) On the axes below, sketch and label graphs of a vs. t for the two trains. Comment on how the graphsrelate to your results in part (b).X

Name: Please show work 3. A passenger train is traveling at 25.0 m/s on a st
Uploaded: 2024-03-05T11:56:34.000Z
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Description: Please show work 3. A passenger train is traveling at 25.0 m/s on a straight track when the engineer spots a freight train, whosecaboose (last car) is 200 m ahead on the same track. The freight train is traveling at 15.0 m/s in the samedirection as t