3. A particle's position along the x-axis as a function of time is given by x(t) = 7.0- 12t + 2.5t² where x is in meters and t is in seconds. a) Determine this particle's initial position, its initial velocity, and its acceleration. You can compare it to a kinematics equation or simply use calculus. b) Note that the initial velocity is negative. At what time will the particle start moving in the positive direction - that is, when will its velocity be zero, just about to become positive? c) Where will the particle be at that time?
3. A particle's position along the x-axis as a function of time is given by x(t) = 7.0- 12t + 2.5t² where x is in meters and t is in seconds. a) Determine this particle's initial position, its initial velocity, and its acceleration. You can compare it to a kinematics equation or simply use calculus. b) Note that the initial velocity is negative. At what time will the particle start moving in the positive direction - that is, when will its velocity be zero, just about to become positive? c) Where will the particle be at that time?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 26P: PROBLEM A race car starting from rest accelerates at a constant rate of 5.00 m/s2, (a) What is the...
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![**Problem 3: Particle Motion Analysis**
A particle's position along the x-axis as a function of time is given by \( x(t) = 7.0 - 12t + 2.5t^2 \), where \( x \) is in meters and \( t \) is in seconds.
**Part (a):**
Determine the particle's initial position, initial velocity, and acceleration. You can compare it to a kinematics equation or simply use calculus.
**Part (b):**
Note that the initial velocity is negative. At what time will the particle start moving in the positive direction—i.e., when will its velocity be zero, just about to become positive?
**Part (c):**
Where will the particle be at that time?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c5a5d39-4610-4542-84f3-e3a5fb07be7c%2Fa34e5b52-f72a-4bdc-8745-81bc79d84d69%2Fj22ben_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 3: Particle Motion Analysis**
A particle's position along the x-axis as a function of time is given by \( x(t) = 7.0 - 12t + 2.5t^2 \), where \( x \) is in meters and \( t \) is in seconds.
**Part (a):**
Determine the particle's initial position, initial velocity, and acceleration. You can compare it to a kinematics equation or simply use calculus.
**Part (b):**
Note that the initial velocity is negative. At what time will the particle start moving in the positive direction—i.e., when will its velocity be zero, just about to become positive?
**Part (c):**
Where will the particle be at that time?
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