3. A half-wave rectifier with a 200 2 load resistor operates from a 120 Vrms 60 Hz household supply current through a 6-to-1 step-down transformer. It uses a silicon diode that can be modelled as having a Vf = 0.9 V drop for any current. vs(t) VL (t) RL (a) What is the peak voltage, us,peak, of the secondary? What is the peak voltage, UL,peak of the rectified output? (b) For what fraction of the cycle (in percentage) does the diode conduct? (c) What is the average output voltage, VL?

3. A half-wave rectifier with a 200 2 load resistor operates from a 120 Vrms 60 Hz household supply current through a 6-to-1 step-down transformer. It uses a silicon diode that can be modelled as having a Vf = 0.9 V drop for any current. vs(t) VL (t) RL (a) What is the peak voltage, us,peak, of the secondary? What is the peak voltage, UL,peak of the rectified output? (b) For what fraction of the cycle (in percentage) does the diode conduct? (c) What is the average output voltage, VL?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

6. A halfwave rectifier(HWR) has an AC input of 14.14Vrms. A Si diode rectifier is connected such that it will conduct during the negative half cyle while a 5K ohm resistor is connected in parallel with the output (Vo).
8.What is the effect of increasing the value of the capacitance In single phase half wave with RL 9. Give an example of a practical case of half-wave uncontrolled rectifier with RL load connected in parallel with C. 10. Propose another circuit(s) to convert AC signal to DC signal.
Q1 A. Design a clamper to perform Silicon diodes 10 V 2.7 V the function indicated in Figure shown below. Design B. Clip the output waveform to -10 V -17.3 V (+0.7 V and -0.7 V).
Draw the circuit diagram of a single phase full-wave uncontrolled rectifier with R-load. Describe its principle of operation. Draw the waveforms of: input voltage, voltage across the load, current through the diodes and their voltage. Write the expressions for: the average output voltage Vd, the maximum reverse voltage across the diode and the standard transformer power. Describe what the difference will be if a capacitor is added in parallel with the load at the output. 1.
For the circuit shown in the Figure, if the diodes are silicon diodes with VD(on)=0.7 V, and VIn=50 sin wt V, V1 =7 V and V2 =13 V, then the value of VOUT (p-p) is: R1 D, D2 VIN VOUT vi E v2= Ca. 19.4 V Ob. 17.4 V Cc. 15.4 V Cd. 21.4 V
Electrical Engineering - elctronic Please solve the question quickly
Consider the full-wave rectifier circuit shown below, where• vS(t) is a sinusoidal signal with a peak value (Vs = 5 V).• Diodes are modelled using constant voltage model with VDO = 0.7 V• The ac line voltage has an rms value of 120 V and a frequency (f) = 60 Hza) Calculate the transformer turns ratio. b) Plot in the same graph signal vS(t) and the output signal vO(t) versus time (t) (show all details including amplitudes, time instances, etc.) c) Calculate the rms value of the output signal vO(t). (hint: sin2(x) = 0.5(1- cos(2x))) d) If a capacitor C=3.58 F is connected across R = 10 k, repeat (b) in a new graph
A half-wave rectifier circuit has an input voltage of 60V for the entire swing of the input signal from the secondary winding of the transformer. If the load resistance is 9on and a shunt capacitor is connected therein: 1. Draw the circuit 2. Solve the following unknown values. a. The peak voltage Vm b. the average output voltage Volave) c. the average load current Iolauel, d. the rms load voltage Vojcmal, e. the rms load current Iotms) f. the ripple factor RF of the output voltage, g. the rms ripple voltage Vrima) h. the average diode current I Diave) i. the rms diode current Ipicmsi, j. the peak inverse voltage PIV of the diode, k. the average output power Polac I. the DC output power Potdc) m.the frequency fr of the output ripple voltage, n. the input power factor PF.
lution H.W5 Design the single-phase half wave controlled rectifier has a purely resistive load of R=1002 and the average output voltage varied from 30V to 120V.
Answr all the questions one by one and solve all the unknown values giving all the correct details Let the last digit of the ID = 9
one SCR in anti parallel with firing angel of 90° for the 30. A single-phase voltage controller, using a diode, feeds a load R and Vs = 230 V. For a SCR, the PMMC voltage connected across R would read