3. A coil of 1000 turns is wound on the central limb. The magnetic path from A to B by way of outer limbs have a mean length of 100cm each and an effective cross – sectional area of 5 sqcm. The central limb is 25cm long and 5sqcm cross – sectional area. The air gap is 0.8cm long. Calculate the current flowing through the coil to produce a flux of 0.3mWb in the air gap. The relative permeability of the core material is 800 (neglect leakage and fringing) -B-

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3. A coil of 1000 turns is wound on the central limb. The magnetic path from A to B by
way of outer limbs have a mean length of 100cm each and an effective cross –
sectional area of 5 sqcm. The central limb is 25cm long and 5sqcm cross – sectional
area. The air gap is 0.8cm long. Calculate the current flowing through the coil to
produce a flux of 0.3mWb in the air gap. The relative permeability of the core
material is 800 (neglect leakage and fringing)
Transcribed Image Text:3. A coil of 1000 turns is wound on the central limb. The magnetic path from A to B by way of outer limbs have a mean length of 100cm each and an effective cross – sectional area of 5 sqcm. The central limb is 25cm long and 5sqcm cross – sectional area. The air gap is 0.8cm long. Calculate the current flowing through the coil to produce a flux of 0.3mWb in the air gap. The relative permeability of the core material is 800 (neglect leakage and fringing)
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