3. A 6.50 kg block is pressed against a vertical wall by a force (F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.41 and the directional angle 8 for the force is 46º. Determine the magnitude of the force (F) when the block is about to slide up the wall. N
3. A 6.50 kg block is pressed against a vertical wall by a force (F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.41 and the directional angle 8 for the force is 46º. Determine the magnitude of the force (F) when the block is about to slide up the wall. N
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![### Problem 3:
A 6.50 kg block is pressed against a vertical wall by a force (\(\vec{F}\)), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.41 and the directional angle \(\theta\) for the force is 46°. Determine the magnitude of the force (\(\vec{F}\)) when the block is about to slide up the wall.
**Given:**
- Mass of the block, \(m = 6.50 \text{ kg}\)
- Coefficient of static friction, \(\mu_s = 0.41\)
- Angle of force, \(\theta = 46^\circ\)
**Required:**
- Magnitude of the force, \(\vec{F}\), in Newtons (N) when the block is about to slide up the wall.
**Diagram Explanation:**
The diagram below shows a block pressed against a vertical wall with a force \(\vec{F}\) at an angle \(\theta\). The force is directed at an angle higher than the left of the horizontal axis, making an impact on the vertical and horizontal friction components with the wall.
![Force Diagram](https://via.placeholder.com/100 "Block pressed against vertical wall")
[Input Box: ] ________ N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd0a9c9c-b0c8-47bb-88dc-3ac08f167320%2Fda2e7267-7475-4023-bbbd-7375f5499b1d%2F5jyaobq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem 3:
A 6.50 kg block is pressed against a vertical wall by a force (\(\vec{F}\)), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.41 and the directional angle \(\theta\) for the force is 46°. Determine the magnitude of the force (\(\vec{F}\)) when the block is about to slide up the wall.
**Given:**
- Mass of the block, \(m = 6.50 \text{ kg}\)
- Coefficient of static friction, \(\mu_s = 0.41\)
- Angle of force, \(\theta = 46^\circ\)
**Required:**
- Magnitude of the force, \(\vec{F}\), in Newtons (N) when the block is about to slide up the wall.
**Diagram Explanation:**
The diagram below shows a block pressed against a vertical wall with a force \(\vec{F}\) at an angle \(\theta\). The force is directed at an angle higher than the left of the horizontal axis, making an impact on the vertical and horizontal friction components with the wall.
![Force Diagram](https://via.placeholder.com/100 "Block pressed against vertical wall")
[Input Box: ] ________ N
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