3. A 2.00-m long air track rests on a horizontal surface with a 10.0-cm high support under one end. A 50.0-g glider (a cart-like object that floats on a cushion of air) is released from rest et the elevated end of the air track. For the purposes of this problem, use the approximation of 10.0 m/s² for the acceleration due to gravity near Earth's surface. ituetion described in the problem stotom

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### Physics Problem on Inclined Plane and Air Track

#### Problem Statement:

A 2.00-m long air track rests on a horizontal surface with a 10.0-cm high support under one end. A 50.0-g glider (a cart-like object that floats on a cushion of air) is released from rest at the elevated end of the air track. For the purposes of this problem, use the approximation of 10.0 m/s² for the acceleration due to gravity near Earth's surface.

#### Tasks:

a. **Draw a pictorial representation of the situation described in the problem statement.**

   *Hint: Sketch an inclined plane with a 2.00-meter length and one end elevated by 10.0 cm.*

b. **Determine the angle of elevation of the air track.**

   *Hint: Use trigonometric ratios (sin, cos, tan) based on the height and length of the track.*

c. **Find the acceleration of the glider.**

   *Hint: Consider the component of gravitational acceleration acting along the inclined plane.*

d. **How fast will the glider be moving when it has traveled 100 cm down the inclined plane?**

   *Hint: Use kinematic equations to determine the final velocity, considering initial velocity and constant acceleration.*

e. **How long will it take the glider to travel 100 cm down the inclined plane?**

   *Hint: Use kinematic equations to find time, based on distance, initial velocity, and acceleration.*

#### Solutions:

1. **Pictorial Representation of the Situation:**
   
    Illustrate an inclined plane with a length of 2.00 meters. The lower end of the track is on the ground, while the upper end is elevated by 10.0 cm.

2. **Angle of Elevation (θ):**
   \[
   \text{tan}(\theta) = \frac{\text{height}}{\text{base}} = \frac{10.0 \, \text{cm}}{200 \, \text{cm}} = \frac{0.1}{2} = 0.05
   \]
   \[
   \theta = \text{tan}^{-1}(0.05) \approx 2.86^\circ
   \]

3. **Acceleration of the Glider (a):**
   \[
   a = g \cdot \sin(\
Transcribed Image Text:### Physics Problem on Inclined Plane and Air Track #### Problem Statement: A 2.00-m long air track rests on a horizontal surface with a 10.0-cm high support under one end. A 50.0-g glider (a cart-like object that floats on a cushion of air) is released from rest at the elevated end of the air track. For the purposes of this problem, use the approximation of 10.0 m/s² for the acceleration due to gravity near Earth's surface. #### Tasks: a. **Draw a pictorial representation of the situation described in the problem statement.** *Hint: Sketch an inclined plane with a 2.00-meter length and one end elevated by 10.0 cm.* b. **Determine the angle of elevation of the air track.** *Hint: Use trigonometric ratios (sin, cos, tan) based on the height and length of the track.* c. **Find the acceleration of the glider.** *Hint: Consider the component of gravitational acceleration acting along the inclined plane.* d. **How fast will the glider be moving when it has traveled 100 cm down the inclined plane?** *Hint: Use kinematic equations to determine the final velocity, considering initial velocity and constant acceleration.* e. **How long will it take the glider to travel 100 cm down the inclined plane?** *Hint: Use kinematic equations to find time, based on distance, initial velocity, and acceleration.* #### Solutions: 1. **Pictorial Representation of the Situation:** Illustrate an inclined plane with a length of 2.00 meters. The lower end of the track is on the ground, while the upper end is elevated by 10.0 cm. 2. **Angle of Elevation (θ):** \[ \text{tan}(\theta) = \frac{\text{height}}{\text{base}} = \frac{10.0 \, \text{cm}}{200 \, \text{cm}} = \frac{0.1}{2} = 0.05 \] \[ \theta = \text{tan}^{-1}(0.05) \approx 2.86^\circ \] 3. **Acceleration of the Glider (a):** \[ a = g \cdot \sin(\
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