3. 4. M M M8 M8 5. Σ 6. n=1 1. I = 2. I = 3. I = (-1)n+122n32n n! 5. I = (-1)n+122n-132n (2η)! (-1)n+122n-132n n! (-1)n+122n32n n! (part 2 of 4) Use the Taylor series for el the integral I= k = 0 n Σ k = 0 Σ k = 0 00 4. I = Σ k = 0 k = 0 χη = 12erdr dx. 1 k!(2k + 1) (-1) k -2.32k k! (-1) k 2k + 1 (-1) k k!(2k + 1) 1 k! 2n+1 χη x²n+1 -2.32k to evaluate 2.32k+1 -2.32k+1 -2.3²k+1 (part 1 of 4) Find the Maclaurin series for the function sin23x . 1. Σ M8 M8 2. n=1 f(x) = (-1)n+122n-132n (2η)! (−1)n+122n32n (2η)! η 2η 22η
3. 4. M M M8 M8 5. Σ 6. n=1 1. I = 2. I = 3. I = (-1)n+122n32n n! 5. I = (-1)n+122n-132n (2η)! (-1)n+122n-132n n! (-1)n+122n32n n! (part 2 of 4) Use the Taylor series for el the integral I= k = 0 n Σ k = 0 Σ k = 0 00 4. I = Σ k = 0 k = 0 χη = 12erdr dx. 1 k!(2k + 1) (-1) k -2.32k k! (-1) k 2k + 1 (-1) k k!(2k + 1) 1 k! 2n+1 χη x²n+1 -2.32k to evaluate 2.32k+1 -2.32k+1 -2.3²k+1 (part 1 of 4) Find the Maclaurin series for the function sin23x . 1. Σ M8 M8 2. n=1 f(x) = (-1)n+122n-132n (2η)! (−1)n+122n32n (2η)! η 2η 22η
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Transcribed Image Text:3.
4.
M M M8 M8
5. Σ
6.
n=1
1. I =
2. I =
3. I =
(-1)n+122n32n
n!
(-1)n+122n-132n
(2η)!
5. I =
(−1)n+122n-132n
n!
(-1)n+122n32n
n!
(part 2 of 4)
Use the Taylor series for e
the integral
k = 0
I=
n
Σ
k = 0
Σ
k = 0
00
4. I = Σ
k = 0
- Σ
k = 0
an
(−1)k
k!
= 12erdr
1
k!(2k + 1)
1
(-1) k
k!(2k + 1)
2n+1
χη
x²n+1
-2.32k
-2.32k
k!
dx.
(-1) k
-2.32k+1
2k + 1
to evaluate
2.32k+1
-2.3²k+1
(part 1 of 4)
Find the Maclaurin series for the function
f(x) sin23x .
1. Σ
M8 M8
2.
n=1
=
(-1)n+122n-132n
(2η)!
(−1)n+122n32n
(2n)!
η 2η
22η
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