1 1 1 Thus 10.3.73 16k2+8k-3 = (4k+3)(4k-1), so 4k – 1 4k +3 4 16k2 + 8k - 3 (4k +3)(4k - 1) 1 -1- 1 1. SO %3D This series telescopes, so Sn 4n – 1 the series given is equal to 4. k=0 4k - 1 4k +3 1 the sum of the series is equal to lim Sn = 4 n-00

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