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3. 4. 5. 6. y(1.5, 5) fy = f(x) (2, 8) Ay = f(x) 6 y= g(x) 3- (-2, 8) 8F (-2, 0) (2, 0) -3 3 71, -3) үз, - 12) Ty= f(x)\ (-1,0). [ (4, 0). (-3, –12), 3 -4 -2 - (1, 2) -12- 4 y = g(x) -4- y= g(x)\ (a) f(x) > 0 (b) f(x) < 0 (a) g(x) <0 (b) g(x) 2 0 (a) g(x) > f(x) (b) f(x) >g(x) (a) f(x)

3. 4. 5. 6. y(1.5, 5) fy = f(x) (2, 8) Ay = f(x) 6 y= g(x) 3- (-2, 8) 8F (-2, 0) (2, 0) -3 3 71, -3) үз, - 12) Ty= f(x)\ (-1,0). [ (4, 0). (-3, –12), 3 -4 -2 - (1, 2) -12- 4 y = g(x) -4- y= g(x)\ (a) f(x) > 0 (b) f(x) < 0 (a) g(x) <0 (b) g(x) 2 0 (a) g(x) > f(x) (b) f(x) >g(x) (a) f(x)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3. 4. 5. 6. y(1.5, 5) fy = f(x) (2, 8) Ay = f(x) 6 y= g(x) 3- (-2, 8) 8F (-2, 0) (2, 0) -3 3 71, -3) үз, - 12) Ty= f(x)\ (-1,0). [ (4, 0). (-3, –12), 3 -4 -2 - (1, 2) -12- 4 y = g(x) -4- y= g(x)\ (a) f(x) > 0 (b) f(x) < 0 (a) g(x) <0 (b) g(x) 2 0 (a) g(x) > f(x) (b) f(x) >g(x) (a) f(x) <g(x) (b) f(x) z g(x)
Transcribed Image Text:3. 4. 5. 6. y(1.5, 5) fy = f(x) (2, 8) Ay = f(x) 6 y= g(x) 3- (-2, 8) 8F (-2, 0) (2, 0) -3 3 71, -3) үз, - 12) Ty= f(x)\ (-1,0). [ (4, 0). (-3, –12), 3 -4 -2 - (1, 2) -12- 4 y = g(x) -4- y= g(x)\ (a) f(x) > 0 (b) f(x) < 0 (a) g(x) <0 (b) g(x) 2 0 (a) g(x) > f(x) (b) f(x) >g(x) (a) f(x) <g(x) (b) f(x) z g(x)
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