3. 3A (17 points) Find the coordinates of the "Center of Mass" of the homogeneous thin plate shown in the figure. Show all your calculations and the result. 2 cm 4 cm X 3B (17 points) Find the coordinates of the "Center of Mass" of the homogeneous thin plate shown in the figure. Show all your calculations and the result. 4 cm 1 cm 1 cm
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- Consider (Figure 1) Assume F = 380 N Figure 3 m 4m Part A Determine the moment of force F about point O Express the result as a Cartesian vector Enter the x, y and components of the moment of force separated by commas. Express your answers in kilonewton-meters to three significant figures. View Available Hint(s) ✓ Hint 1. Cartesian Vector Formulation for the Moment of a Force ijk Ty T. where Tz. F F F Ty, T, represent the zy, z components of the position vector drawn from O to any point on the line of action of the force, F., Fy, F represent the z. y. z components of the force vector in this problem, r, and F. components are equal to zero, since the line of action of the force lies in the z-y plane For simplicity, consider using vector r that lies on either of the axes z or y, since in that case you need only one non-zero coordinate to express its position If zy, z coordinate axes are established, then the moment equation can be written in determinant form as Mo=rx F = T₂ Mo = Submit…Suppose objects A and B have an elastic, one-dimensional collision. Object A, with mass 2 kg, is initially traveling to the right with a speed of 5 m/s. Object B, with mass 3 kg, is initially traveling in the opposite direction with a speed of 9 m/s. Determine the speed and direction of each object after the collision. Please use the built-in math editor, keep units in all of your equations, and show all of your steps to receive full credit.What is the y component Fy of the resultant force?
- Part E Find x-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) Fx = Submit Part F Fy= μà Submit Value Find y-component of F = (20.0 N, 36.9° counterclockwise from the positive y-axis). Express your answer with the appropriate units. View Available Hint(s) µÅ Units Value ? Units ?1. The block in the figure to the right remains motionless against the wall because of an applied force and the force of static friction between the block and the wall. The coefficient of static friction is μs. Which equation correctly describes the magnitude of the frictional force between the wall and the block?a. Ff=(mgcosθ)μsb. Ff= (Fasinθ–mg) μsc. Ff= (Facosθ – mg) μsd. Ff= Facosθμse. Ff= (Facosθ + mg) μsSuppose F1 = 290 N, answer both parts to the problem listed.
- 56. A forklift is used to offload freight from a delivery truck. Together the forklift and its contents weigh 800 Ib, and the weight is evenly distributed among four wheels. The ramp is inclined 14° from the horizontal. F F1 a. Write the force vector F in terms of i and j representing the weight against a single tire. b. Find the component vector of F parallel to the ramp. Round values to 1 decimal place. c. Find the magnitude of the force needed to keep the forklift from rolling down the ramp. Round to the nearest pound.he FBD of the block should have looked like this. 1. A contestant in a winter sporting event pushes a block of ice of mass m across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μs, and the coefficient of kinetic friction is μk. θ is the angle the force makes with the x-axis. In this part, we are going to set-up Newton's second Law equations for the cases(1) when the ice block just starts moving, and(2) when it is accelerating to the right with an acceleration a. All answers are symbolic. ALL ANSWERS ARE CASE-SENSITIVE. Subpart 1: Newton's Second Law along the y-axis (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and θ. In both scenarios, there is no acceleration along the y-direction, therefore, ay=0.…take time and answer these questions correctly.
- HW1.4. 2D Moment resultant Two forces lying in the x-y plane are defined by their magnitudes and direction angles, as shown in the figure below. Force F₁ has a magnitude F₁ = 360 N, an angle 0₁ = 109°, and acts at point A (310, 0) mm. Force F₂ has a magnitude F₂ = 270 N, an angle 02 = 56°, and acts at point B = (0,385) mm. Determine the total moment about point O due to these two forces. Remember to follow the standard sign convention for clockwise (-) and counter-clockwise (+) moments. y B 10 02 F₂ F₁ A 0₁ X TEGINGENM Support Cable 37° M As shown in the diagram above, a rigid rod of mass M is hinged at its left end against a wall. A block of mass M hangs on the right edge of the rod. A support cable attached to the right end of the rod forms an angle of 37 degrees with horizontal. The tension in the string is 1,057 N. Calculate the mass M of the rod and the block. Express your answer in kilograms and round to the nearest tenth (1 decimal).Constants Part A For the vectors A, B, and C in the figure (Figure 1), find the scalar products Submit Request Answer Part B Figure 1 of 1 Submit Request Answer B (15.0 m) Part C 30.0% D (10.0 m) 53.0 25.0 C (12.0 m) A (8.00 m) Submit Request Answer