**Equilibrium Constant Expression for a Chemical Reaction****Problem Statement:**Write the equilibrium constant expression for the reaction:\[ \text{4 HCl (g) + O}_2 \text{ (g)} \rightleftharpoons 2 \text{H}_2\text{O (l) + 2 Cl}_2 \text{ (g)} \]**Solution:**The equilibrium constant expression (\(K_c\)) for this reaction is based on the concentrations of the gaseous reactants and products at equilibrium. Pure liquids, such as water in this reaction, are not included in the expression.**Equilibrium Constant Expression:**\[ K_c = \frac{[\text{Cl}_2]^2}{[\text{HCl}]^4 [\text{O}_2]} \]Where:- \([\text{Cl}_2]\) is the concentration of chlorine gas,- \([\text{HCl}]\) is the concentration of hydrogen chloride gas,- \([\text{O}_2]\) is the concentration of oxygen gas.This expression highlights how the concentration of each species at equilibrium influences the overall equilibrium constant for the reaction.

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Answered: 3- Write the equilibrium constant…

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Chemistry

3- Write the equilibrium constant expression for the reaction 4 HCl (g) + O2 (g) 2 H₂O (1) + 2 Cl2 (g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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