3) There is an air bubble in the plastic block that happens to be shaped like a plano-convex lens as shown. (In other words, the top of the bubble is flat, and the bottom is spherical.) Trace the path followed by the light rays as the light refracts through the air bubble. Ignore any reflections. Briefly explain your reasoning. (No calculations are necessary. Assume the air bubble has an index of refraction equal to 1, and the surrounding plastic indicated by the grid has an index 1.4)

3) There is an air bubble in the plastic block that happens to be shaped like a plano-convex lens as shown. (In other words, the top of the bubble is flat, and the bottom is spherical.) Trace the path followed by the light rays as the light refracts through the air bubble. Ignore any reflections. Briefly explain your reasoning. (No calculations are necessary. Assume the air bubble has an index of refraction equal to 1, and the surrounding plastic indicated by the grid has an index 1.4)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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8)
A convex lens of focal length 10 cm is used to obtain an image that is twice as large as the object. a) How far from the lens should the object be placed to produce an inverted image? b) How far from the lens should the object be placed to produce a non-inverted image? c) Draw a ray diagram showing how the inverted and non-inverted images are formed. Label the principal rays being used (two rays are sufficient). { Please use a separate diagram for the inverted and non-inverted cases. }
4. A small statue 3 cm in height is placed 22.0 cm in front of a concave spherical mirror with a focal length of 10.0 cm. (A folded sheet of paper can be used as a straight edge) a) Use the line below to draw the ray diagram (assume each mark is 2 cm apart). Use at least 3 of the principal rays and mark the focal point and center of curvature. b) What is the distance to the image? c) What is the magnification of the image? d) Is the image real or virtual, why?
Please only typing answer.. Two thin lenses with focal lengths f1=+150 mm and f2=-100 mm are located d=60 mm apart in air. a) Find, for the lens combination, the effective focal length (feff) and the distances from the lens centres to the principal points (h1 and h2) and the distance between the principle planes (); b) Sketch the system, showing the principal planes and labelling the distances in a). Describe (numerically) the effect of adding the lens 2 to power of the optical system.
Needs Complete typed solution with 100 % accuracy.
E. Light is incident from air (n = 1.0003) on the rectangular piece of glass shown below. 60° 30° 55° 35° 1. Determine the index of refraction of the glass Determine the speed of light in the glass shown
c.) real or virtual d.) inverted or noninverted e.) same or opposite
c.) real or virtual d.) inverted or noninverted e.) same or opposite
9
A nearsighted woman has a far point of 280 cmcm . Part A What kind of lens, converging or diverging, should be prescribed for her to see distant objects more clearly? converging diverging she doesn't need lens not enough information to estimate Part B What refractive power should the lens have? Express your answer in diopters.
1. (Old exam problem) Consider the thin lens imaging arrangement shown below. Answer the following. [A ray trace is not needed - use the thin lens image law.] iris lens 20 1 25 detector 150 20 + source Units: mm f = 50 a) The detector is to be placed at the image plane. Find the position of the image plane. b) If the height of the image is 1 mm, what is the height of the object? c) Suppose the diagram is drawn to scale. What is the aperture stop? d) Find the location and size (radius) of the entrance pupil. e) Find the location and size (radius) of the exit pupil. f) If you had to guess, what is the field stop?
2. In the image below, an incident ray shines at an angle onto two layers of class. The first layer has an index of refraction of 1.47. The second layer is of an unknown index. You have determined the point at which the ray exits the second layer of glass. You will need a protractor to measure angles in this problem. (A) Determine the angle of refraction of the ray inside the first material. (B) Trace the path of the ray through the first and second layers of materials on the picture below. (C) Determine the unknown index of refraction in the second material. (D) Determine direction of and draw the path of the ray after it exits the second layer. point where ray exits second layer. air n2 = ? ni = 1.47 air incident ray