2. In the image below, an incident ray shines at an angle onto two layers of class. The first layer has an index of refraction of 1.47. The second layer is of an unknown index. You have determined the point at which the ray exits the second layer of glass. You will need a protractor to measure angles in this problem. (A) Determine the angle of refraction of the ray inside the first material. (B) Trace the path of the ray through the first and second layers of materials on the picture below. (C) Determine the unknown index of refraction in the second material. (D) Determine direction of and draw the path of the ray after it exits the second layer.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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2. In the image below, an incident ray shines at an angle onto two layers of class. The first layer has an
index of refraction of 1.47. The second layer is of an unknown index. You have determined the
point at which the ray exits the second layer of glass. You will need a protractor to measure angles
in this problem.
(A) Determine the angle of refraction of the ray inside the first material.
(B) Trace the path of the ray through the first and second layers of materials on the picture
below.
(C) Determine the unknown index of refraction in the second material.
(D) Determine direction of and draw the path of the ray after it exits the second layer.
point where ray exits
second layer.
air
n2 = ?
ni = 1.47
air
incident
ray
Transcribed Image Text:2. In the image below, an incident ray shines at an angle onto two layers of class. The first layer has an index of refraction of 1.47. The second layer is of an unknown index. You have determined the point at which the ray exits the second layer of glass. You will need a protractor to measure angles in this problem. (A) Determine the angle of refraction of the ray inside the first material. (B) Trace the path of the ray through the first and second layers of materials on the picture below. (C) Determine the unknown index of refraction in the second material. (D) Determine direction of and draw the path of the ray after it exits the second layer. point where ray exits second layer. air n2 = ? ni = 1.47 air incident ray
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