**18. Light starts in a medium of index of refraction n1, passes into a medium of index n2, where n2 > n1, and finally passes into air.** The diagram accompanying the text shows a rectangular box segmented into three layers, representing different media through which light travels. The topmost layer is labeled "air," the middle layer is labeled "n2," and the bottom layer is labeled "n1." **Details of the Diagram:** - The bottom segment (`n1`) is shaded differently to indicate a unique medium with a refractive index `n1`. - The middle segment (`n2`) is also shaded and represents another medium with a refractive index `n2`, which is greater than `n1`. - Above these two segments is the unshaded segment labeled "air." **Diagram Explanation:** - **Light Path A:** This arrow represents the path of light as it moves through the media and bends due to the change in refractive index from `n1` to `n2` and then from `n2` to air. - **Light Path B to E:** Similar paths are drawn to show the light bending at different angles as it passes through the different layers. The label options for the question and the answers choices are: **A. A** **B. B** **C. C** **D. D** **E. E** Students are likely asked to identify which path corresponds to the correct description of how light refracts when transitioning between these indices of refraction. Understanding Snell's Law \( (n1 \cdot \sin(\theta1) = n2 \cdot \sin(\theta2)) \) would be critical in answering this question correctly.

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**18. Light starts in a medium of index of refraction n1, passes into a medium of index n2, where n2 > n1, and finally passes into air.**

The diagram accompanying the text shows a rectangular box segmented into three layers, representing different media through which light travels. The topmost layer is labeled "air," the middle layer is labeled "n2," and the bottom layer is labeled "n1."

**Details of the Diagram:**

- The bottom segment (`n1`) is shaded differently to indicate a unique medium with a refractive index `n1`.
- The middle segment (`n2`) is also shaded and represents another medium with a refractive index `n2`, which is greater than `n1`.
- Above these two segments is the unshaded segment labeled "air."

**Diagram Explanation:**

- **Light Path A:** This arrow represents the path of light as it moves through the media and bends due to the change in refractive index from `n1` to `n2` and then from `n2` to air. 
- **Light Path B to E:** Similar paths are drawn to show the light bending at different angles as it passes through the different layers.

The label options for the question and the answers choices are:

**A. A**  
**B. B**  
**C. C**  
**D. D**  
**E. E**

Students are likely asked to identify which path corresponds to the correct description of how light refracts when transitioning between these indices of refraction. Understanding Snell's Law \( (n1 \cdot \sin(\theta1) = n2 \cdot \sin(\theta2)) \) would be critical in answering this question correctly.
Transcribed Image Text:**18. Light starts in a medium of index of refraction n1, passes into a medium of index n2, where n2 > n1, and finally passes into air.** The diagram accompanying the text shows a rectangular box segmented into three layers, representing different media through which light travels. The topmost layer is labeled "air," the middle layer is labeled "n2," and the bottom layer is labeled "n1." **Details of the Diagram:** - The bottom segment (`n1`) is shaded differently to indicate a unique medium with a refractive index `n1`. - The middle segment (`n2`) is also shaded and represents another medium with a refractive index `n2`, which is greater than `n1`. - Above these two segments is the unshaded segment labeled "air." **Diagram Explanation:** - **Light Path A:** This arrow represents the path of light as it moves through the media and bends due to the change in refractive index from `n1` to `n2` and then from `n2` to air. - **Light Path B to E:** Similar paths are drawn to show the light bending at different angles as it passes through the different layers. The label options for the question and the answers choices are: **A. A** **B. B** **C. C** **D. D** **E. E** Students are likely asked to identify which path corresponds to the correct description of how light refracts when transitioning between these indices of refraction. Understanding Snell's Law \( (n1 \cdot \sin(\theta1) = n2 \cdot \sin(\theta2)) \) would be critical in answering this question correctly.
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