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3 The equation for the instantaneous discharging capacitor is given by Vo is the initial voltage and of the circuit. The tasks are to: a) Draw a graph of voltage against time for voltage across a v=Voe, where is the time constant Vo=12V and 1=2s, between t=0s and t=10s. b) c) Differentiate v=12e Calculate the gradient at t=2s and t=4s. and calculate the value of d) e) dv at t=2s and t=4s. dt Compare your answers for part b and part c. Calculate the second derivative of the instantaneous voltage d²v dr²

3 The equation for the instantaneous discharging capacitor is given by Vo is the initial voltage and of the circuit. The tasks are to: a) Draw a graph of voltage against time for voltage across a v=Voe, where is the time constant Vo=12V and 1=2s, between t=0s and t=10s. b) c) Differentiate v=12e Calculate the gradient at t=2s and t=4s. and calculate the value of d) e) dv at t=2s and t=4s. dt Compare your answers for part b and part c. Calculate the second derivative of the instantaneous voltage d²v dr²

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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3 The equation for the instantaneous discharging capacitor is given by Vo is the initial voltage and of the circuit. The tasks are to: a) Draw a graph of voltage against time for voltage across a v=Voe, where is the time constant V₁=12V and 1=2s, between t=0s and t=10s. b) Calculate the gradient at t=2s and t=4s. c) Differentiate v=12e and calculate the value of dv at t=2s and t=4s. dt d) Compare your answers for part b and part c. e) Calculate the second derivative of the instantaneous voltage d²v dt²
Transcribed Image Text:3 The equation for the instantaneous discharging capacitor is given by Vo is the initial voltage and of the circuit. The tasks are to: a) Draw a graph of voltage against time for voltage across a v=Voe, where is the time constant V₁=12V and 1=2s, between t=0s and t=10s. b) Calculate the gradient at t=2s and t=4s. c) Differentiate v=12e and calculate the value of dv at t=2s and t=4s. dt d) Compare your answers for part b and part c. e) Calculate the second derivative of the instantaneous voltage d²v dt²
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