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- 3 sin( – 5t)). Let r(t) = (2t³ + 4, − 5e¯ - Find f(t)dt (don't include the +C) fr(t)dt = { "

- 3 sin( – 5t)). Let r(t) = (2t³ + 4, − 5e¯ - Find f(t)dt (don't include the +C) fr(t)dt = { "

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3.2.7

- 4t Let r(t) = (2+³ + 4, − 5e¯ fr(t)dt fr(t)dt = ( Find " - – 3 sin( – 5t)). (don't include the +C) |)+C
Transcribed Image Text:- 4t Let r(t) = (2+³ + 4, − 5e¯ fr(t)dt fr(t)dt = ( Find " - – 3 sin( – 5t)). (don't include the +C) |)+C
Find the unit tangent vector to the curve defined by r(t) = (5t, – 5t, √1 – t²) at t = 0. T(0) =
Transcribed Image Text:Find the unit tangent vector to the curve defined by r(t) = (5t, – 5t, √1 – t²) at t = 0. T(0) =
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Since you have asked multiple question, we will solve the first question for you. If you
want any specific question to be solved then please specify the question number or post
only that question.

 

Consider the curve r→t=2t5+4,-5e-4t,-3sin-5t.

The objective is to find ∫r→tdt.

Use the integration formulas:

Power rule formula: ∫xndx=xn+1n+1+C

∫eatdt=eata+C and ∫sinatdt=-1acosat+C

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