-3 Question: We know the concentration of copper sulfate to be 0.01 mol dm from other experiment, and so we also know (from suitable tables) that the ionic activity coefficient of the copper sulfate solution is 0.404. The measure electrode potential was E cupper ion (1) without considering the activity coefficient (2) considering the activity coefficient. = 0.269 and E Cu+,Cu = 0.340. Calculate the concentration of Cu+,Cu

-3 Question: We know the concentration of copper sulfate to be 0.01 mol dm from other experiment, and so we also know (from suitable tables) that the ionic activity coefficient of the copper sulfate solution is 0.404. The measure electrode potential was E cupper ion (1) without considering the activity coefficient (2) considering the activity coefficient. = 0.269 and E Cu+,Cu = 0.340. Calculate the concentration of Cu+,Cu

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please answer B: data attached if needed:
2. Draw a galvanic cell containing Zn/Zn²+ (0.25 M) couple and Ag/AgC1(3.5M KCl) electrode connected with a salt bridge. The standart electrode potential of for Zn/Zn²+ and Ag/Ag+ are -0.76 V and 0.80 V respectively. Ksp(Ag/AgCl):1.7x10-10 a) Draw a galvanic cell and write the oxidation - reduction reactions occurring at each electrode and net cell reaction. b) Calculate the cell potential.
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Experiment 2: What is the cell potential of the electrochemical cell indicated by the cell diagram? Zn(s)|1 M Zn(NO,),(aq)||1 M Cu(NO, ),(aq)|Cu(s) O 1.100 V O-0.420 V -1.100 V 0.420 V
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Question 9 What is the cell potential for the following reaction at 25 *C? Ni(s) + Cu2*(0.010 M) – Ni²*c0.0010 M) + Cu*(1.0 M) SRP: E' Ni2*/Ni = -0.25 V; E° Cu2+/cu* = +0.15 V O 0.43 V 0.40 V 0.37 V 0.34 V
From the initial measurements you determine the electrode slope is -56.7 mV. You measure the initial potential of an unknown to be 84.5 mV. After the addition of 0.1027 M fluoride the potential drops to 39.9 mV. What is the molarity of fluoride in the original, undiluted, unknown? Answer is 3.97. How to derive?
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Q20
Enter your answer in the provided box. What is the potential of a cell made up of Zn / Zn2+ and Cu / Cu²+ half-cells at 25°C if [Zn2*] = 0.31 M and [Cu2*] = 0.41 M ? V