[3] Predict the major products in the following reactions. (a) AICI 3

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please explain each one.

Is it alkylation or acylation?

**Predict the Major Products in the Following Reactions**

1. **Reaction (a):**
   - **Reactants:** 
     - 2-Chloropropane (CH₃CHClCH₃)
     - Benzene (C₆H₆)
     - Aluminum Chloride (AlCl₃)
   - **Reaction Type:** Friedel-Crafts Alkylation
   - **Explanation:** The presence of aluminum chloride suggests an electrophilic substitution reaction where the alkyl group (isopropyl) will be transferred to the benzene ring.

2. **Reaction (b):**
   - **Reactants:** 
     - 1-Chlorobutane (CH₃(CH₂)₂CH₂Cl)
     - Benzene (C₆H₆)
     - Aluminum Chloride (AlCl₃)
   - **Reaction Type:** Friedel-Crafts Alkylation
   - **Explanation:** The chlorine atom on the butyl chain will act as a leaving group, allowing the butyl group to attach to the benzene ring, facilitated by the AlCl₃ catalyst.

3. **Reaction (c):**
   - **Reactants:** 
     - 3-Bromo-1-propene (CH₂=CHCH₂Br)
     - Benzene (C₆H₆)
     - Aluminum Chloride (AlCl₃)
   - **Reaction Type:** Friedel-Crafts Alkylation
   - **Explanation:** The allyl group (CH₂=CHCH₂) is transferred to the benzene ring in the presence of AlCl₃, resulting in the substitution of the allylic position onto the ring.

**Diagrams:**

Each reaction is depicted with:
- A chloro or bromo substituted alkane/alkene.
- An arrow indicating the reaction's direction.
- Benzene and aluminum chloride beneath the arrow, suggesting their involvement in the reaction.

These reactions demonstrate the typical process of alkyl group substitution from an alkyl halide onto an aromatic ring using a Lewis acid catalyst.
Transcribed Image Text:**Predict the Major Products in the Following Reactions** 1. **Reaction (a):** - **Reactants:** - 2-Chloropropane (CH₃CHClCH₃) - Benzene (C₆H₆) - Aluminum Chloride (AlCl₃) - **Reaction Type:** Friedel-Crafts Alkylation - **Explanation:** The presence of aluminum chloride suggests an electrophilic substitution reaction where the alkyl group (isopropyl) will be transferred to the benzene ring. 2. **Reaction (b):** - **Reactants:** - 1-Chlorobutane (CH₃(CH₂)₂CH₂Cl) - Benzene (C₆H₆) - Aluminum Chloride (AlCl₃) - **Reaction Type:** Friedel-Crafts Alkylation - **Explanation:** The chlorine atom on the butyl chain will act as a leaving group, allowing the butyl group to attach to the benzene ring, facilitated by the AlCl₃ catalyst. 3. **Reaction (c):** - **Reactants:** - 3-Bromo-1-propene (CH₂=CHCH₂Br) - Benzene (C₆H₆) - Aluminum Chloride (AlCl₃) - **Reaction Type:** Friedel-Crafts Alkylation - **Explanation:** The allyl group (CH₂=CHCH₂) is transferred to the benzene ring in the presence of AlCl₃, resulting in the substitution of the allylic position onto the ring. **Diagrams:** Each reaction is depicted with: - A chloro or bromo substituted alkane/alkene. - An arrow indicating the reaction's direction. - Benzene and aluminum chloride beneath the arrow, suggesting their involvement in the reaction. These reactions demonstrate the typical process of alkyl group substitution from an alkyl halide onto an aromatic ring using a Lewis acid catalyst.
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