3 Ni(NO3)2•6H2O (s) + 2 Na3PO4 (aq) --> Ni3(PO4)2 (s) + 6 NaNO3 (aq) If 5.226 g Ni(NO3)2•6H2O is allowed to react with 25.00 ml of 0.1000 M Na3PO4 . How many grams of Ni3(PO4)2 can form? Start by giving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it? Select one: a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2 c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 d. None of these e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2 g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2 If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni3(PO4)2 will form? Select one: a. 0.3379 g b. 2.192 g c. 0.4575 g d. 2.650 g e. None of these f. 6.577 g g. 13.25 g h. 7.492 g i. 0.9150 g j. 1.325 g k. 3.746 g If all of the sodium phosphate reacts, that is 25.00 ml of 0.1000 M Na3PO4. How many grams of Ni3(PO4)2 can form? Select one: a. 0.4575 g b. 3.746 g c. 1.325 g d. 2.192 g e. 13.25 g f. 6.577 g g. 0.9150 g h. 2.650 g i. None of these j. 7.492 g k. 0.3379 g Using your answers from questions 2 and 3, if 5.226 g nickel (II) nitrate hexahydrate are permitted to react with 25.00 ml of 0.1000 M Na3PO4, what is the theoretical yield of Ni3(PO4)2? Select one: a. 2.650 g b. 0.4575 g c. 1.325 g d. 0.9150 g e. 2.192 g f. None of these g. 7.492 g h. 3.746 g i. 6.577 g j. 0.3379 g k. 13.25 g In the reaction of 5.226 g Ni(NO3)2•6H2O with 25.00 ml of 0.1000 M Na3PO4 , what is the limiting reagent? 3 Ni(NO3)2•6H2O (s) + 2 Na3PO4 (aq) --> Ni3(PO4)2 (s) + 6 NaNO3 (aq) Select one: a. Na3PO4 b. Ni(NO3)2•6H2O c. Ni3(PO4)2 d. None of these e. NaNO3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3 Ni(NO₃)₂•6H₂O (s) + 2 Na₃PO₄ (aq) --> Ni₃(PO₄)₂ (s) + 6 NaNO₃ (aq)

If 5.226 g Ni(NO₃)₂•6H₂O is allowed to react with 25.00 ml of 0.1000 M Na₃PO₄ . How many grams of Ni₃(PO₄)₂ can form? Start by giving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it?

Select one:

a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O

b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2

c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2

d. None of these

e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O

f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2

g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2

h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2

If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni₃(PO₄)₂ will form?

Select one:

a. 0.3379 g

b. 2.192 g

c. 0.4575 g

d. 2.650 g

e. None of these

f. 6.577 g

g. 13.25 g

h. 7.492 g

i. 0.9150 g

j. 1.325 g

k. 3.746 g

If all of the sodium phosphate reacts, that is 25.00 ml of 0.1000 M Na₃PO₄. How many grams of Ni₃(PO₄)₂can form?

Select one:

a. 0.4575 g

b. 3.746 g

c. 1.325 g

d. 2.192 g

e. 13.25 g

f. 6.577 g

g. 0.9150 g

h. 2.650 g

i. None of these

j. 7.492 g

k. 0.3379 g

Using your answers from questions 2 and 3, if 5.226 g nickel (II) nitrate hexahydrate are permitted to react with 25.00 ml of 0.1000 M Na₃PO₄, what is the theoretical yield of Ni₃(PO₄)₂?

Select one:

a. 2.650 g

b. 0.4575 g

c. 1.325 g

d. 0.9150 g

e. 2.192 g

f. None of these

g. 7.492 g

h. 3.746 g

i. 6.577 g

j. 0.3379 g

k. 13.25 g

In the reaction of 5.226 g Ni(NO₃)₂•6H₂O with 25.00 ml of 0.1000 M Na₃PO₄ , what is the limiting reagent?

3 Ni(NO₃)₂•6H₂O (s) + 2 Na₃PO₄ (aq) --> Ni₃(PO₄)₂ (s) + 6 NaNO₃ (aq)

Select one:

a. Na₃PO₄

b. Ni(NO₃)₂•6H₂O

c. Ni₃(PO₄)₂

d. None of these

e. NaNO₃

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