3-Methylbutanal undergoes an aldol reaction to form 3-hydroxy-2-isopropyl-5-methylhexanal as shown. 10% NaOH 5 °C но Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows. Do not delete any pre-drawn bonds, charges, or lone pairs. If you accidentally delete a vital part of the structure, use the undo button on the lower left of the drawing canvas. B. A second molecule of aldchyde is introduced. Complete the product formed and draw curved arrows. A. Draw curved arrows. Select Draw Rings More Erase Select Draw Rings More Erase HO H H H H C. Complete the structure. Then draw curved arrows. Select Draw Rings More Erase H The final products

3-Methylbutanal undergoes an aldol reaction to form 3-hydroxy-2-isopropyl-5-methylhexanal as shown. 10% NaOH 5 °C но Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and curved arrows. Do not delete any pre-drawn bonds, charges, or lone pairs. If you accidentally delete a vital part of the structure, use the undo button on the lower left of the drawing canvas. B. A second molecule of aldchyde is introduced. Complete the product formed and draw curved arrows. A. Draw curved arrows. Select Draw Rings More Erase Select Draw Rings More Erase HO H H H H C. Complete the structure. Then draw curved arrows. Select Draw Rings More Erase H The final products

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter23: Carbonyl Condensation Reactions

Section23.SE: Something Extra

Problem 56AP

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Concept explainers

Reactions at the Alpha Carbon Atom

The position next to the ketone or aldehyde functional group is termed as alpha position and the reaction which occurs at alpha position is called alpha substitution reaction. In an alpha substitution reaction, the alpha proton atom is substituted by an electrophile by the formation of an enol intermediate or enolate ion intermediate. Most of the carbonyl compounds go through an alpha substitution reaction.

Question

3-Methylbutanal undergoes an aldol reaction to form 3-hydroxy-2-isopropyl-5-methylhexanal as shown.
10% NaOH
5 °C
HO
Complete the mechanism for the reaction by adding missing atoms, bonds, charges, nonbonding electrons, and
curved arrows. Do not delete any pre-drawn bonds, charges, or lone pairs. If you accidentally delete a vital part of
the structure, use the undo button on the lower left of the drawing canvas.
A. Draw curved arrows.
B. A second molecule of aldehyde is
introduced. Complete the product formed and
Select Draw Rings More
Erase
draw curved arrows.
H
Select Draw Rings More
Erase
cHO
H
H
C. Complete the structure. Then draw curved arrows.
Select
Draw
Rings More
Erase
The final products
H

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