3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + In(cos~¹((√1- (sin(x))²))) boundary from x=1 fox = 2 In(cos-¹((√1- (sin(x))²))) N cm Activate Wir Go to Settings t cm What is the change in length of the spring?
3 m B -3 m- -3 m- C 2.25 m k = 200 N/m- -3 m D E 4 m F 3 m 3 m 3m 3 m A -0-90° p=0.1 -2m-1m- F(x)= -Inx Inx+-Inx F(x)= -Inx -Inx boundary from x=1 to x = 2 + In(cos~¹((√1- (sin(x))²))) boundary from x=1 fox = 2 In(cos-¹((√1- (sin(x))²))) N cm Activate Wir Go to Settings t cm What is the change in length of the spring?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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- Show complete solution, including the process of integration, solving for the area/moment of the area via integration, evaluation of the definite integral and algebraic/trigonometric manipulation.
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![A
2.25 m
-4 m
-e=90° µ=0.1
3m
3 m
k= 200 N /m
F(x) =
N
xur_° + xu°
boundary from x =1 to x = 2
3 m
What is the change in length of the spring?
-2m-F1 m-
3 m
3 m
3 m-
F(x) =
Inx
cm
boundary from x =1 to x = 2
3 m
3 m
Activate Wir
Go to Settings te
B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9626780b-0ca5-4980-9554-ad7e6eda260d%2Fb429f836-e851-443f-a74e-01eb08eff3a4%2Fy0uhshi_processed.png&w=3840&q=75)
Transcribed Image Text:A
2.25 m
-4 m
-e=90° µ=0.1
3m
3 m
k= 200 N /m
F(x) =
N
xur_° + xu°
boundary from x =1 to x = 2
3 m
What is the change in length of the spring?
-2m-F1 m-
3 m
3 m
3 m-
F(x) =
Inx
cm
boundary from x =1 to x = 2
3 m
3 m
Activate Wir
Go to Settings te
B
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