3- In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g at the place in m/s?? a) 2mV(I/k) b) 2(l/g)2 c) 2nv(I/mg) 2V(1/g) e) 2mV(1/m)
3- In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g at the place in m/s?? a) 2mV(I/k) b) 2(l/g)2 c) 2nv(I/mg) 2V(1/g) e) 2mV(1/m)
Related questions
Question
![3- In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the
measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g
at the place in m/s? ?
a)
2nV(I/k)
b)
2(l/g)2
c)
2nv(I/mg)
2V(1/g)
e)
2TV(1/m)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb77f18ef-ad78-4142-9314-30471d6cd469%2F3b1f02f1-08b7-465f-b97c-a08af625c7d2%2Fz22ojb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3- In an experiment for determining the gravitational acceleration g of a place with the help of a simple pendulum, the
measured time period square is plotted against the string length of the pendulum in the figure. What is the value of g
at the place in m/s? ?
a)
2nV(I/k)
b)
2(l/g)2
c)
2nv(I/mg)
2V(1/g)
e)
2TV(1/m)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)