### Problem 14**Question: What is the total kinetic energy of an object that is 5 kg and moving 25 m/s due West? (2 pts.)****Solution:**The kinetic energy (KE) of an object is calculated using the formula:\[ KE = \frac{1}{2} mv^2 \]Where:- \( m \) is the mass of the object- \( v \) is the velocity of the objectAlternatively, the formula can be expressed as:\[ KE = 0.5 \times m \times v \times v \]Plug in the given values:\[ KE = 0.5 \times \_\_\_\_\_ \times \_\_\_\_\_ \]\( \left( \text{Note: Fill in the box with the appropriate numerical values for mass and velocity.} \right) \)\[ \_\_\_\_\_ \times \_\_\_\_\_ \times \_\_\_\_\_ \times \_\_\_\_\_ = \_\_\_\_\_ \text{ J} \]The answer is expressed in Joules (J), the SI unit for energy.

Given Mass (m) = 5 kg Speed (v) = 25 m/s Kinetic energy of the object KE = (1/2) mv2

Answered: 14. What is the total kinetic energy of…

14. What is the total kinetic energy of an object that is 5 kg and moving 25 m/s due West? (2 pts.) KE= 1/2mv^2 KE = 0.5 * m* v * v or

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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