3) If the magnitude of the resultant force is to be 500 N, directed along the positive y-axis, determine the magnitude of force F and its direction O in Figure 1.

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Chapter1: Units, Trigonometry. And Vectors
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Can someone plz explain this more thoroughly. I need help with math and concepts..Q3
The given force we have is:
700N at an angle 15° anticlockwise from -y axis.
And the required resultant force is 500N directed along +y axis.
Now, the x component of the force F should be equal to the x component of force 700N since there is no
resultant force in the x direction.
→700 cos 15° = F cos 0
F cos 0 = 676.14 N
Step2
b)
And the net force in the y axis should be equal to 500N.
→F sin 0 – 700 sin 15° = 500
→F sin 0 = 500 + 181.17
→F sin 0 = 681.17N
So, the angle of force F should be:
F sin 0
681.17'
F cos 0
(676.14,
(681.17)
tan 0 =
\676.14,
>0 = 45.212°
And the force F will be:
F cos 45.212°
= 676.14
→F = 959.76N
Therefore, The force F is 959.76N and the angle 0 is 45.212°
Transcribed Image Text:The given force we have is: 700N at an angle 15° anticlockwise from -y axis. And the required resultant force is 500N directed along +y axis. Now, the x component of the force F should be equal to the x component of force 700N since there is no resultant force in the x direction. →700 cos 15° = F cos 0 F cos 0 = 676.14 N Step2 b) And the net force in the y axis should be equal to 500N. →F sin 0 – 700 sin 15° = 500 →F sin 0 = 500 + 181.17 →F sin 0 = 681.17N So, the angle of force F should be: F sin 0 681.17' F cos 0 (676.14, (681.17) tan 0 = \676.14, >0 = 45.212° And the force F will be: F cos 45.212° = 676.14 →F = 959.76N Therefore, The force F is 959.76N and the angle 0 is 45.212°
2) In Figure 1,
force and its direction, measured counterclockwise from the positive x-axis.
60° and F = 450 N, determine the magnitude of the resultant
F,
15°
700 N
Figure 1
3) If the magnitude of the resultant force is to be 500 N, directed along the
positive y-axis, determine the magnitude of force F and its direction O in
Figure 1.
Transcribed Image Text:2) In Figure 1, force and its direction, measured counterclockwise from the positive x-axis. 60° and F = 450 N, determine the magnitude of the resultant F, 15° 700 N Figure 1 3) If the magnitude of the resultant force is to be 500 N, directed along the positive y-axis, determine the magnitude of force F and its direction O in Figure 1.
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