(3) Find the density of the random variable X representing the number of correctly placed letters when n = 4 letters are randomly placed into the four envelopes. The following answers are proposed for the density, I Values of X 0 1 P1 2 3 4 P2 P3 P4 Probabilities Po where • P1 = P2 = P3 = 0, p4 = . Pa = 0, p4 = 4. P4 = (a) Po = (b) Po = Pi = 7. P2 3. PI=. Pa = (d) po = PI = P2 = (e) None of the above (c) Po = Pa P4 = Then correct answer is: (a) (b) (c) (d) (e) N/A (Select One)

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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(3) Find the density of the random variable X representing the number of correctly placed letters when n = 4 letters are randomly placed
into the four envelopes.
The following answers are proposed for the density,
Values of X
1
Po
4
P2 P3
P4
Probabilities
P1
where
(a) po = . P1 = P2 = . P3 = 0, p4 = .
Pa = 0. p4 = 4.
, P3 =, P4 =
.
%3D
%3D
(b) Po = P1
P2 =
%3D
(c) Po =D . Pi= 금, Pa =
21 P2 =
(e) None of the above
Then correct answer is:
(d) po = PI
. Pa = P4 =
(a)
(Б)
(c)
(d)
(e)
N/A
(Select One)
Transcribed Image Text:(3) Find the density of the random variable X representing the number of correctly placed letters when n = 4 letters are randomly placed into the four envelopes. The following answers are proposed for the density, Values of X 1 Po 4 P2 P3 P4 Probabilities P1 where (a) po = . P1 = P2 = . P3 = 0, p4 = . Pa = 0. p4 = 4. , P3 =, P4 = . %3D %3D (b) Po = P1 P2 = %3D (c) Po =D . Pi= 금, Pa = 21 P2 = (e) None of the above Then correct answer is: (d) po = PI . Pa = P4 = (a) (Б) (c) (d) (e) N/A (Select One)
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