3) Consider the curve C which is the intersection of the surfaces shown in the attached figure. If C: r(t) = (x(t), y(t), z(t)), t ≤ [a, b], is a parameterization of C, so one possible way to r(t) is: X A) r(t) = (2 cost, 1+4 cost, z(t)), t€ [0, 1] B) r(t) = (x(t), 4+4 cost, 3 sint), t€ [0, 1] C) r(t) = (3 sint, y(t), 2 cost), t = [0, €] D) r(t) = (2 cost, 4+4 cost, z(t)), t€ [0, 1] 4 = 1 2 с 52 21 = 0 Y
3) Consider the curve C which is the intersection of the surfaces shown in the attached figure. If C: r(t) = (x(t), y(t), z(t)), t ≤ [a, b], is a parameterization of C, so one possible way to r(t) is: X A) r(t) = (2 cost, 1+4 cost, z(t)), t€ [0, 1] B) r(t) = (x(t), 4+4 cost, 3 sint), t€ [0, 1] C) r(t) = (3 sint, y(t), 2 cost), t = [0, €] D) r(t) = (2 cost, 4+4 cost, z(t)), t€ [0, 1] 4 = 1 2 с 52 21 = 0 Y
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![3) Consider the curve C which is the intersection
of the surfaces shown in the attached figure.
If C: r(t) = (x(t), y(t), z(t)), t ≤ [a, b],
is a parameterization of C, so one possible way to
r(t) is:
X
A) r(t) = (2 cost, 1+4 cost, z(t)), t€ [0, 1]
B) r(t) = (x(t), 4+4 cost, 3 sint), t€ [0, 1]
C) r(t) = (3 sint,
y(t), 2 cost), t ≤ [0, 1]
D) r(t) = (2 cost, 4+4 cost, z(t)), t€ [0, 1]
4
= 1
2
с
52
21
= 0
Y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb9027ed-a7cd-4af9-80b3-ae2c1df1d725%2Fe47b9e14-025c-48ef-b0d6-063110e6585c%2Fpd0fnbd_processed.png&w=3840&q=75)
Transcribed Image Text:3) Consider the curve C which is the intersection
of the surfaces shown in the attached figure.
If C: r(t) = (x(t), y(t), z(t)), t ≤ [a, b],
is a parameterization of C, so one possible way to
r(t) is:
X
A) r(t) = (2 cost, 1+4 cost, z(t)), t€ [0, 1]
B) r(t) = (x(t), 4+4 cost, 3 sint), t€ [0, 1]
C) r(t) = (3 sint,
y(t), 2 cost), t ≤ [0, 1]
D) r(t) = (2 cost, 4+4 cost, z(t)), t€ [0, 1]
4
= 1
2
с
52
21
= 0
Y
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