Determine the distance from the line y = x + 1 to the parabola y2 = x. (Hint: Let (x, y) be a point on the line and (w, z) a point on the parabola. You want to minimize (x - w)2 + ( y - z)2.)

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine the distance from the line y = x + 1 to the parabola y2 = x. (Hint: Let (x, y) be a point on the line and (w, z) a point on the parabola. You want to minimize (x - w)2 + ( y - z)2.)

Expert Solution
Step 1 To determine:

The shortest distance from the line y = x + 1 to the parabola y2=x.

Equation of line y = x + 1is shown by red color and parabola y2=x is shown by blue color

Calculus homework question answer, step 1, image 1

 

Step 2

The shortest distance should lie on the perpendicular line between both the line and the curve.

Slope of y = x + 1dydx=1

Slope of normal =-1   (product of slope of perpendicular lines is -1)

Similarly , Slope of tangent to curve y2=x:  1          ...(i)

 

Differentiate y2=x with respect to x.

2ydydx=1dydx=12y 

 

From (i)

12y=1y=12

 

 

Step 3

Substitute y=12in (i)

122=xx=14

The coordinate of P is 14,12.

 

Now equation of normal PQ:

 y-12=-1x-14y=-x+14+12y=-x+34         (ii)

 

Add the given equation of line and (ii),

2y=1+34y=78

Substitute in the given equation and solve for x

78=x+1x=78-1=-18

Thus, coordinates of Q are -18,78.

 

 

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