3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following 2 information: 1 COCl₂(g) + H₂O(1)→ CH₂Cl2 (1) + O2(g) 1 H₂0 (1) + Cl₂(g) → HCl(g) + O2(g) 1 4 + H₂O(1)→ COCl (g) Answer: 8 x 107 2 1 1 CH₂Cl₂ (1) + H₂ (9) + 7 3 + - 02 (9) Ke = 5.40 x 10-³ Kc = 149 Kc = 1.25 x 10-4

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3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following
2
information:
COCl2 (g) + H₂0 (1)→ CH₂Cl2 (1) + O2(g)
1
1
/H₂0 (1) +
CoCl2 (9) + H₂0 (1)→
Answer: 8 x 107
Cl₂(g) → HCl(g) + +-
A
1
02 (9)
3
+ H₂(g) +702 (9)
H2
CH₂Cl₂ (1) +
CH₂Cl₂ (1)
Kc = 5.40 x 10-³
Kc = 149
Kc = 1.25 x 10-4
Transcribed Image Text:3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following 2 information: COCl2 (g) + H₂0 (1)→ CH₂Cl2 (1) + O2(g) 1 1 /H₂0 (1) + CoCl2 (9) + H₂0 (1)→ Answer: 8 x 107 Cl₂(g) → HCl(g) + +- A 1 02 (9) 3 + H₂(g) +702 (9) H2 CH₂Cl₂ (1) + CH₂Cl₂ (1) Kc = 5.40 x 10-³ Kc = 149 Kc = 1.25 x 10-4
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