3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following 2 information: 1 COCl₂(g) + H₂O(1)→ CH₂Cl2 (1) + O2(g) 1 H₂0 (1) + Cl₂(g) → HCl(g) + O2(g) 1 4 + H₂O(1)→ COCl (g) Answer: 8 x 107 2 1 1 CH₂Cl₂ (1) + H₂ (9) + 7 3 + - 02 (9) Ke = 5.40 x 10-³ Kc = 149 Kc = 1.25 x 10-4
3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following 2 information: 1 COCl₂(g) + H₂O(1)→ CH₂Cl2 (1) + O2(g) 1 H₂0 (1) + Cl₂(g) → HCl(g) + O2(g) 1 4 + H₂O(1)→ COCl (g) Answer: 8 x 107 2 1 1 CH₂Cl₂ (1) + H₂ (9) + 7 3 + - 02 (9) Ke = 5.40 x 10-³ Kc = 149 Kc = 1.25 x 10-4
Introductory Chemistry: A Foundation
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ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
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Chapter10: Energy
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Problem 66AP: Calculate the enthalpy change when 1.0(1 g of methane is burned in excess oxygen according to the...
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![3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following
2
information:
COCl2 (g) + H₂0 (1)→ CH₂Cl2 (1) + O2(g)
1
1
/H₂0 (1) +
CoCl2 (9) + H₂0 (1)→
Answer: 8 x 107
Cl₂(g) → HCl(g) + +-
A
1
02 (9)
3
+ H₂(g) +702 (9)
H2
CH₂Cl₂ (1) +
CH₂Cl₂ (1)
Kc = 5.40 x 10-³
Kc = 149
Kc = 1.25 x 10-4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1077e877-4e25-45d6-8c49-9aaf109d8b6e%2F8a7741e2-8fa7-42ac-bb70-ba268d57ae03%2Fn7nfywk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3) Calculate Kc for the reaction: H₂(g) + Cl2 (g) → 2 HCl(g) using the following
2
information:
COCl2 (g) + H₂0 (1)→ CH₂Cl2 (1) + O2(g)
1
1
/H₂0 (1) +
CoCl2 (9) + H₂0 (1)→
Answer: 8 x 107
Cl₂(g) → HCl(g) + +-
A
1
02 (9)
3
+ H₂(g) +702 (9)
H2
CH₂Cl₂ (1) +
CH₂Cl₂ (1)
Kc = 5.40 x 10-³
Kc = 149
Kc = 1.25 x 10-4
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