3) At 207 °C, Kp = 0.276 for the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g) a. If 0.100 mole of PCl5(g) is placed in an otherwise empty 12.0-L vessel at 207 °C, calculate the partial pressures of PCl5(g), PCl3 (g), and Cl2(g) at equilibrium. b. In another experiment the total pressure of an equilibrium mixture is 2.00 atm at 207 °C. What mass of PCl5 was introduced into an otherwise empty 5.00-L vessel to reach this equilibrium position?
3) At 207 °C, Kp = 0.276 for the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g) a. If 0.100 mole of PCl5(g) is placed in an otherwise empty 12.0-L vessel at 207 °C, calculate the partial pressures of PCl5(g), PCl3 (g), and Cl2(g) at equilibrium. b. In another experiment the total pressure of an equilibrium mixture is 2.00 atm at 207 °C. What mass of PCl5 was introduced into an otherwise empty 5.00-L vessel to reach this equilibrium position?
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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3) At 207 °C, Kp = 0.276 for the reaction
PCl5(g) ⇌ PCl3(g) + Cl2(g)
a. If 0.100 mole of PCl5(g) is placed in an otherwise empty 12.0-L vessel at 207 °C, calculate the partial pressures of PCl5(g), PCl3 (g), and Cl2(g) at equilibrium.
b. In another experiment the total pressure of an equilibrium mixture is 2.00 atm at 207 °C. What mass of PCl5 was introduced into an otherwise empty 5.00-L vessel to reach this equilibrium position?
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The reaction is given by,
Find- The partial pressures of PCl5(g), PCl3(g), and Cl2(g) at equilibrium and The mass of PCl5 when the total pressure of an equilibrium mixture is 2.00 atm.
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