3 and 4 subparts only else I won't give upvote
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Q1. 3 and 4 subparts only else I won't give upvote
![Q1. Analyze the time complexity for following code segments/ functions.
i.
1. int count = 0;
2. for (int i = n; i> 0; i /= 2)
3.
ii.
for (i=1; i<=n; i++)
for (j=1; j<=log(i); j++)
PRINT "HELLO JUET !";
for (int j = 0; j<i; j++)
count += 1;
4.
iv.
void fun(int n, int arr[])
1. {
int i = 0
iii.
if (n==1)
return;
for (int i=1; i<=n; i++)
{
2.
for(; i<n; i++)
for(j-0;j <n && arr[i] < arr[j];j++)
Print"i+j";
3.
for (int j=1; j<=n; j++)
{
printf("*");
break;
6. }
}
V.
vi.
1.For I = 1 to n-1
void function(int n)
{
int count = 0;
for (int i-n/2; i<=n; i++)
for (int j-1; j<=n; j = 2 * j)
2.
For J = 0 to (n-I-1)
If a[J] > a[J+1] then,
Set temp = a[J]
Set a[J] = a[J+1]
Set a[J+1] = temp
3.
4.
5.
for (int k-1; k<=n; k = k * 2)
count++;
6.
vii.
viii.
void function(int n)
{
int count = 0;
for (int i=n/2; i<=n; i++)
for (int j=1; j+n/2<=n; j = j++)
1. For I= 0 to n-2
2.
min=I
3.
For J= I+1 to (n-1)
4.
If a[min] > a[J]
for (int k=1; k<=n; k = k * 2)
count++;
5.
min=J
Set temp = a[min]
Set a[min] = a[I]
Set a[I] = temp
6.
}
7.
8.
456](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F61f44b34-bdc1-43b6-b5f3-137baacde6c6%2F9b0b538d-e346-4fc2-a8b5-f4df5ff56ece%2Fcc4eefa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q1. Analyze the time complexity for following code segments/ functions.
i.
1. int count = 0;
2. for (int i = n; i> 0; i /= 2)
3.
ii.
for (i=1; i<=n; i++)
for (j=1; j<=log(i); j++)
PRINT "HELLO JUET !";
for (int j = 0; j<i; j++)
count += 1;
4.
iv.
void fun(int n, int arr[])
1. {
int i = 0
iii.
if (n==1)
return;
for (int i=1; i<=n; i++)
{
2.
for(; i<n; i++)
for(j-0;j <n && arr[i] < arr[j];j++)
Print"i+j";
3.
for (int j=1; j<=n; j++)
{
printf("*");
break;
6. }
}
V.
vi.
1.For I = 1 to n-1
void function(int n)
{
int count = 0;
for (int i-n/2; i<=n; i++)
for (int j-1; j<=n; j = 2 * j)
2.
For J = 0 to (n-I-1)
If a[J] > a[J+1] then,
Set temp = a[J]
Set a[J] = a[J+1]
Set a[J+1] = temp
3.
4.
5.
for (int k-1; k<=n; k = k * 2)
count++;
6.
vii.
viii.
void function(int n)
{
int count = 0;
for (int i=n/2; i<=n; i++)
for (int j=1; j+n/2<=n; j = j++)
1. For I= 0 to n-2
2.
min=I
3.
For J= I+1 to (n-1)
4.
If a[min] > a[J]
for (int k=1; k<=n; k = k * 2)
count++;
5.
min=J
Set temp = a[min]
Set a[min] = a[I]
Set a[I] = temp
6.
}
7.
8.
456
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