3) A hydrogen atom starts out in the following linear combination of the stationary states. n = 2,1 = 1,m = 1 and n = 2,1 = 1, m = −1 1 Y(r,0) = (211 + 21-1) √2 a. Construct (r, t). b. Find the expectation value of the potential energy.
3) A hydrogen atom starts out in the following linear combination of the stationary states. n = 2,1 = 1,m = 1 and n = 2,1 = 1, m = −1 1 Y(r,0) = (211 + 21-1) √2 a. Construct (r, t). b. Find the expectation value of the potential energy.
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Transcribed Image Text:3) A hydrogen atom starts out in the following linear combination of the stationary states. n = 2,1 =
1, m = 1 and n = 2,1 = 1, m = -1
Y(r, 0)
=
1
√2
(211 + 21-1)
a. Construct (r, t).
b. Find the expectation value of the potential energy.
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