3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes are to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes are to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
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![3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes
are
to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d43d606-1651-4e6c-a7be-ce858e19f618%2Fd552c973-af60-4cb2-892d-a22329902a42%2Fn7obsof_processed.png&w=3840&q=75)
Transcribed Image Text:3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes
are
to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
Expert Solution
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Concept and Principle:
- The double slit experiment consists of a light source, two closely placed slits, and a screen. When the light is passed through the slits it forms an interference pattern of alternating bright and dark fringes along with a central maximum.
- The bright fringes are formed due to constructive interference and dark fringes are formed due to destructive interference.
- The distance to mth bright fringe from the central maximum caused by constructive interference is given by,
Here m is the order of the maxima, λ is the wavelength of the source, L is the distance from the slit to the screen's center point, and d is the slit spacing.
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