3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes are to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?

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3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes
are
to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
Transcribed Image Text:3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes are to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
Expert Solution
Concept and Principle:
  • The double slit experiment consists of a light source, two closely placed slits, and a screen. When the light is passed through the slits it forms an interference pattern of alternating bright and dark fringes along with a central maximum.

 

  • The bright fringes are formed due to constructive interference and dark fringes are formed due to destructive interference.

 

  • The distance to mth bright fringe from the central maximum caused by constructive interference is given by,

ym=mλLd

Here m is the order of the maxima, λ is the wavelength of the source, L is the distance from the slit to the screen's center point, and d is the slit spacing.

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