3- A bomb of mass M with initial velocity vo and suddenly explodes to two fragments of mass M/3 and 2M/3 as shown in the figure. The explosion was not elastic and the gain in the energy equals Q = -SMvž. Find the velocities of the two fragments after the explosion. [Assume that vo, vi and vz all on the same axis] (1.5) 2MS M
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- 1. The launcher is set to launch a projectile horizontally. Once launched, the projectile will immediately go into the pendulum (the “catcher” in the diagram), causing the pendulum to swing. Considering momentum, sum all the momenta of the situation after the ball is launched but before it goes into the pendulum. Do not consider the recoil of the launcher. 2. When the ball gets caught by the pendulum, what kind of collision is this (elastic or inelastic)? What is the momentum after the collision? Using conservation of momentum, derive an equation for the velocity of the ball/pendulum combo immediately after the ball is caught (and before the pendulum starts to swing upward). The equation can depend on the mass of the ball, the mass of the pendulum, and the initial velocity of the ball. 3. The pendulum will start to swing upwards. At the beginning of its swing, what kind ofenergy does the pendulum have? It will swing up to a certain angle where it will temporarily stop. What kind of…A 500Kg Ford focus automobile is initially travelling at vi, focus=(60i + 20j)Km/hr when it inelastically collides with a 16.7Mg semitruck initally traveling at vi,truck=(-30i-110j)Km/hr. problems: a) what is the final velocity immediately after the inelastic collision? b) assume that, just after the collision , the ford focus and semitruck begin to slide across the pavement due to a uniform kinetic friction with coefficient uk=0.45. how far will they slide before coming to a stop.Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei (ªHe) from gold-197 nuclei (197 Au). The energy of the incoming helium nucleus was 7.28 × 10-13 J, and the masses of the helium and gold nuclei were 6.68 × 10-27 kg and 3.29 × 10-25 kg, respectively (note that their mass ratio is 4 to 197). (Assume that the helium nucleus travels in the +x direction before the collision.) (a) If a helium nucleus scatters to an angle of 136° during an elastic collision with a gold nucleus, calculate the helium nucleus' final speed (in m/s) and the final velocity (magnitude in m/s and direction counterclockwise from the +x-axis) of the gold nucleus. 4He speed 197 Au velocity t 197 Au direction 14500000 0.0140 -17 m/s X m/s ° counterclockwise from the +x-axis (b) What is the final kinetic energy (in J) of the helium nucleus? 7.02e-13 J
- 3. A ball of mass 25 g traveling east at 12 m/s bounces elastically into a 2nd ball of mass 50 that is traveling west at 4m/s. What are the final velocities and momentum of each ball? (Hint: either solve the systems of equations for momentum and energy simultaneously or come up with a relative velocity system..) Place ball 2 in a moving reference frame so that it's velocity is 0 in this reference frame. In this reference frame ball 1 has 16 m/s initial velocity. Find the final velocities in this moving reference frame. m2 V10 m1 + m2 2m1 m1 v'1F v'2F V10 m1 + m2 Don't forget to come back out of the moving reference frame at the end... (since we added velocities before this time we subtract...a South bound railroad car with mass of 13,000kg moving at 25 m/s collides and couples with a North bound second of mass 20,000kg moving at 15 m/s. What is the magnitude and direction of the common velocity of the cars after this collision>?1. The launcher is set to launch a projectile horizontally. Once launched, the projectile will immediately go into the pendulum (the “catcher” in the diagram), causing the pendulum to swing. Considering momentum, sum all the momenta of the situation after the ball is launched but before it goes into the pendulum. Do not consider the recoil of the launcher. 2. When the ball gets caught by the pendulum, what kind of collision is this (elastic or inelastic)? What is the momentum after the collision? Using conservation of momentum, derive an equation for the velocity of the ball/pendulum combo immediately after the ball is caught (and before the pendulum starts to swing upward). The equation can depend on the mass of the ball, the mass of the pendulum, and the initial velocity of the ball. 3. The pendulum will start to swing upwards. At the beginning of its swing, what kind ofenergy does the pendulum have? It will swing up to a certain angle where it will temporarily stop. What kind of…
- A P 100% BIUA Normal text Arial 12 三 1 2 |. 3 I 4 1. A 0.40kg football is kicked at a velocity of 11m/s. What is the momentum of the ball?-1.20 kg.m/s 2. A student dresses up as sumo for halloween and jumps towards his friend with a velocity of 2.3m/s and a momentum of 506kgm/s. What was the student's mass? 3. The sumo student from problem 2 collides with his friend. Upon colliding he accelerated his friend 8m/ s?. If the collision lasts 1.2s, what was the impulse of the collision? 4. A 0.43kg pumpin is smashed by a zombie student's foot that had a momentum of 432kgm/s. What was the speed of his kick? 5. Calculate the time it took for Frankenstien to punch through a wall with a force of 8,023N resulting in an impulse of 593NS.A radioactive nucleus at rest decays into a second nucleus, an electron, and a neutrino. The electron and neutrino are emitted at right angles and have momenta of pe = 8.95×10-23 kg-m/s and Py = 6.18x10-23 kg. m/s, respectively. (Figure 1) Figure Pnuc (nuc) +y 0 Onuc Pv Pe Part A Determine the magnitude of the momentum of the second (recoiling) nucleus. Express your answer to three significant figures and include the appropriate units. Pnuc = Submit Part B ■ μÅ Value Request Answer Pearson Units Review | Constan ?I. A lump of clay (m = 3.00 kg) is thrown towards a wall at speed v = 3.00 m/s. The lump sticks to the wall. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. II. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 3.00 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. III. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 2.00 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during…
- The impulse experienced by a body is proportional to its change in: velocity squared O momentum Okinetic energy O both 1 and 2Question 5A saturn 5 rocket must travel 17, 800 mph to escape the gravitational pull of the earth and enter space. The rocket weight 6.2 million pounds, and the initial specific impulse lasts 263 seconds. What impulse is required for the rocket to meet the 17, 800 mph momentum in needs, using the formula FT=MV?