3-4 3-2) Find the TRUE magnitude and direction of the RESULTANT FORCE and MOMENT AT POINT A TTTTT Force lbs 6 30° 200 lb 0 200 60% 100 45° FORCE AND COMPONENT DIAGRAM 100 lb/ft e Fx=F.Cos(0) F, =F.Sin(6) 100 70.71 173.21 -70.71 M=Fxd Forces 173.21*6= -2- 1039.26 10.71 * 12' = 848.521 45 Couples 100 lb

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Answer the question.Thank you.
3-4
3-2) Find the TRUE magnitude and direction of the RESULTANT FORCE and MOMENT
AT POINT A
1
/200 Ib
FORCE AND COMPONENT DIAGRAM
Force
lbs
0
200 60%
100
100 45° 70.71
Rx=
30°
e FF.Cos(0) F=F.Sin(0)
A
100 lb/ft
A
173.21
70.71
+M₁
M=Fxd
Forces
Ry=
RESULTANT FORCE AND MOMENT DIAGRAM
173.21*6=
1639,26'
10.71 x 12 =
४५४,521
MR 1887.78 FT.
45
Couples
-MA O
VIO VA
100 lb
Transcribed Image Text:3-4 3-2) Find the TRUE magnitude and direction of the RESULTANT FORCE and MOMENT AT POINT A 1 /200 Ib FORCE AND COMPONENT DIAGRAM Force lbs 0 200 60% 100 100 45° 70.71 Rx= 30° e FF.Cos(0) F=F.Sin(0) A 100 lb/ft A 173.21 70.71 +M₁ M=Fxd Forces Ry= RESULTANT FORCE AND MOMENT DIAGRAM 173.21*6= 1639,26' 10.71 x 12 = ४५४,521 MR 1887.78 FT. 45 Couples -MA O VIO VA 100 lb
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