3-35 The hydraulic lift in a car repair shop has an output diarneter of 30 cm and is to lift cars up to 2000 kg. Deter- mine the fluid gage pressure that must be maintained in the reservoir.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Oil
FIGURE P3-34
65 kPa
SG-072
75 cm
3-35 The hydraulic lift in a car repair shop has an output
diarneter of 30 cm and is to lift cars up to 2000 kg. Deter-
mine the fluid gage pressare that must be maintained in the
reservoir
Air
Water
30 ca
Merury
SG- 13.6
3-36 Freshwater and seawater flowing in parallel horizontal
pipelines are connected to each ather by a double U-tuhe
Air
FIGURE P3-40
Resh
wter
40 cm
341 Repeat Prob. 3-40 for a gage pressure of 45 kPa.
3-42 The top part of a water tank is divided into two com-
partments, as shown in Fig. P3-42. Now a fluid with an
unknown density is poured into ane side, and the water level
rises a certain amount on the other side to compensate for
this effect. Based on the final fluid heights shown on the fig-
ure, determine the density of the fluid added. Assume the liq-
Sea-
wat
10 cm
Mercury
FIGURE P3-36
uid does not mix with water.
107
CHAPTER 3
the two arms is 32 in, detemine the pressure difference
between the two tanks. The densities of ail and mercury are
Unknown
Liguid
45 lbm/ft' and 848 Ibm/ft', respectively.
3-45 Pressure is often given in terms of a liquid calumn
and is expressed as "pressure head." Express the standard
atmospherie pressure in terms of (a) mercury (SG - 13.6),
(b) water (SG = 1.0), and (c) glycerin (SG = 1.26) columns.
Explain why we usually use mereury in manometers,
80 cm
95 cm
WATER
3-46 A simple experiment has long heen used to demon-
strate how negative pressure prevents water from being
spilled out of an inverted glass. A glass that is fully filled by
water and covered with a thin paper is inverted, as shown in
Fig. P3-46. Determine the pressure at the bottom of the
glass, and expluin why water does not fall out.
50 cm
FIGURE P3-42
343 The 500-kg load on the hydraulic lift shown in Fig.
P3-43 is to be raised by pouring oil (p = 780 kp/m') into a
thin tuhe. Determine how high h should be in order to begin
to raise the weight.
Glass
10 cm
Water
LOAD
500 kg
A piece
uf paper
-1.2m
1 em
FIGURE P3-46
3-47 Two chambers with the same fluid at their base are
separated by a piston whose weight is 25 N, as shown in Fig.
P3-47. Calculate the gage pressures in chambers A and B.
FIGURE P3-43
Piston
344E Two eil tanks are connected to each other through a
manometer. If the difference between the mercury levels in
A
A
Air n
Oil
Oil
50 em
10 in
30 cm
25 cm
30 cm
32 in
Water
r
90 cm
-Mercury
FIGURE P3-44E
FIGURE P3-47
108
FLUID MECHANICS
3-50 Consider the system shown in Fig. P3-50. If a change
of 0.7 kPa in the pressure of air causes the brine-mercury
interface in the right column to drop by 5 mm in the brine
level in the right column while the pressure in the brine pipe
remains constant, determine the ratio of AJA
3-48 Consider a double-fluid manometer attached to an air
pipe shown in Fig. P3-48, If the specific gravity of one fluid
is 13.55, determine the specific gravity of the other fluid for
the indicated abhsolute pressure of air. Take the atmospheric
pressure to be 100 kPa. Answer: 5.0
Air
Air
(P= 76 kPa
40 em
Brine
pipe
sd1.1
SG,
Water
22 em
Ara A
Area. A
SG,= 13.55
Mercury
SG- 13.56
Transcribed Image Text:Oil FIGURE P3-34 65 kPa SG-072 75 cm 3-35 The hydraulic lift in a car repair shop has an output diarneter of 30 cm and is to lift cars up to 2000 kg. Deter- mine the fluid gage pressare that must be maintained in the reservoir Air Water 30 ca Merury SG- 13.6 3-36 Freshwater and seawater flowing in parallel horizontal pipelines are connected to each ather by a double U-tuhe Air FIGURE P3-40 Resh wter 40 cm 341 Repeat Prob. 3-40 for a gage pressure of 45 kPa. 3-42 The top part of a water tank is divided into two com- partments, as shown in Fig. P3-42. Now a fluid with an unknown density is poured into ane side, and the water level rises a certain amount on the other side to compensate for this effect. Based on the final fluid heights shown on the fig- ure, determine the density of the fluid added. Assume the liq- Sea- wat 10 cm Mercury FIGURE P3-36 uid does not mix with water. 107 CHAPTER 3 the two arms is 32 in, detemine the pressure difference between the two tanks. The densities of ail and mercury are Unknown Liguid 45 lbm/ft' and 848 Ibm/ft', respectively. 3-45 Pressure is often given in terms of a liquid calumn and is expressed as "pressure head." Express the standard atmospherie pressure in terms of (a) mercury (SG - 13.6), (b) water (SG = 1.0), and (c) glycerin (SG = 1.26) columns. Explain why we usually use mereury in manometers, 80 cm 95 cm WATER 3-46 A simple experiment has long heen used to demon- strate how negative pressure prevents water from being spilled out of an inverted glass. A glass that is fully filled by water and covered with a thin paper is inverted, as shown in Fig. P3-46. Determine the pressure at the bottom of the glass, and expluin why water does not fall out. 50 cm FIGURE P3-42 343 The 500-kg load on the hydraulic lift shown in Fig. P3-43 is to be raised by pouring oil (p = 780 kp/m') into a thin tuhe. Determine how high h should be in order to begin to raise the weight. Glass 10 cm Water LOAD 500 kg A piece uf paper -1.2m 1 em FIGURE P3-46 3-47 Two chambers with the same fluid at their base are separated by a piston whose weight is 25 N, as shown in Fig. P3-47. Calculate the gage pressures in chambers A and B. FIGURE P3-43 Piston 344E Two eil tanks are connected to each other through a manometer. If the difference between the mercury levels in A A Air n Oil Oil 50 em 10 in 30 cm 25 cm 30 cm 32 in Water r 90 cm -Mercury FIGURE P3-44E FIGURE P3-47 108 FLUID MECHANICS 3-50 Consider the system shown in Fig. P3-50. If a change of 0.7 kPa in the pressure of air causes the brine-mercury interface in the right column to drop by 5 mm in the brine level in the right column while the pressure in the brine pipe remains constant, determine the ratio of AJA 3-48 Consider a double-fluid manometer attached to an air pipe shown in Fig. P3-48, If the specific gravity of one fluid is 13.55, determine the specific gravity of the other fluid for the indicated abhsolute pressure of air. Take the atmospheric pressure to be 100 kPa. Answer: 5.0 Air Air (P= 76 kPa 40 em Brine pipe sd1.1 SG, Water 22 em Ara A Area. A SG,= 13.55 Mercury SG- 13.56
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