2x²+5x-3 z²+4x+3 for æ < -3 f (x) = { ka + for - 3< a < 0 2 for æ > 0 3 -

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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b) What type of discontinuity does \( f \) have at \( x = 0 \)? Give a reason for your answer.

c) Find all horizontal asymptotes to the graph of \( f \), if there are any. Show the work that leads to your answer.

d) Find all vertical asymptotes to the graph of \( f \), if there are any. Show the work that leads to your answer.

---

This section of the exercise focuses on analyzing the features of a function \( f \), specifically identifying types of discontinuities and asymptotes.

**Discontinuity Inquiry (b):**
- The prompt asks to determine the type of discontinuity at \( x = 0 \). Discontinuities occur where a function fails to be continuous, which could be due to a jump, a hole (removable discontinuity), or an infinite gap (essential discontinuity).

**Horizontal Asymptotes Exploration (c):**
- The task requires finding any horizontal asymptotes. Horizontal asymptotes indicate the behavior of the function as \( x \) approaches infinity or negative infinity. This usually involves evaluating the limit of \( f(x) \) as \( x \to \infty \) and \( x \to -\infty \).

**Vertical Asymptotes Exploration (d):**
- Here, the focus is on identifying vertical asymptotes, which occur at values of \( x \) where the function heads toward infinity. Typically, these are found by solving for \( x \) values that cause a division by zero or undefined value in \( f(x) \).

To fully address these questions, one must consider the specific form of the function \( f \) and perform algebraic analysis to draw conclusions about its continuity and asymptotic behavior.
Transcribed Image Text:Below is a transcription and explanation intended for an educational website: --- b) What type of discontinuity does \( f \) have at \( x = 0 \)? Give a reason for your answer. c) Find all horizontal asymptotes to the graph of \( f \), if there are any. Show the work that leads to your answer. d) Find all vertical asymptotes to the graph of \( f \), if there are any. Show the work that leads to your answer. --- This section of the exercise focuses on analyzing the features of a function \( f \), specifically identifying types of discontinuities and asymptotes. **Discontinuity Inquiry (b):** - The prompt asks to determine the type of discontinuity at \( x = 0 \). Discontinuities occur where a function fails to be continuous, which could be due to a jump, a hole (removable discontinuity), or an infinite gap (essential discontinuity). **Horizontal Asymptotes Exploration (c):** - The task requires finding any horizontal asymptotes. Horizontal asymptotes indicate the behavior of the function as \( x \) approaches infinity or negative infinity. This usually involves evaluating the limit of \( f(x) \) as \( x \to \infty \) and \( x \to -\infty \). **Vertical Asymptotes Exploration (d):** - Here, the focus is on identifying vertical asymptotes, which occur at values of \( x \) where the function heads toward infinity. Typically, these are found by solving for \( x \) values that cause a division by zero or undefined value in \( f(x) \). To fully address these questions, one must consider the specific form of the function \( f \) and perform algebraic analysis to draw conclusions about its continuity and asymptotic behavior.
### Function Definition and Domain Explanation

The function \( f(x) \) is defined piecewise as follows:

1. For \( x < -3 \):
   \[
   f(x) = \frac{2x^2 + 5x - 3}{x^2 + 4x + 3}
   \]

2. For \( -3 \leq x \leq 0 \):
   \[
   f(x) = kx + \frac{1}{2}
   \]
   where \( k \) is a constant.

3. For \( x > 0 \):
   \[
   f(x) = \frac{x^2}{3x - 1}
   \]

### Context Note
- The piecewise function, \( f(x) \), is divided into three intervals according to the value of \( x \).
- In the first interval (\( x < -3 \)), the function is a rational function, which means the expression is a ratio of two polynomials.
- In the second interval (\( -3 \leq x \leq 0 \)), the function is a linear expression in terms of \( x \), where \( k \) is a constant parameter influencing the slope.
- In the third interval (\( x > 0 \)), the function again takes the form of a rational expression with the numerator being a quadratic polynomial and the denominator a linear polynomial.

This setup should assist learners in understanding how piecewise functions can combine different forms and how their domains are partitioned.
Transcribed Image Text:### Function Definition and Domain Explanation The function \( f(x) \) is defined piecewise as follows: 1. For \( x < -3 \): \[ f(x) = \frac{2x^2 + 5x - 3}{x^2 + 4x + 3} \] 2. For \( -3 \leq x \leq 0 \): \[ f(x) = kx + \frac{1}{2} \] where \( k \) is a constant. 3. For \( x > 0 \): \[ f(x) = \frac{x^2}{3x - 1} \] ### Context Note - The piecewise function, \( f(x) \), is divided into three intervals according to the value of \( x \). - In the first interval (\( x < -3 \)), the function is a rational function, which means the expression is a ratio of two polynomials. - In the second interval (\( -3 \leq x \leq 0 \)), the function is a linear expression in terms of \( x \), where \( k \) is a constant parameter influencing the slope. - In the third interval (\( x > 0 \)), the function again takes the form of a rational expression with the numerator being a quadratic polynomial and the denominator a linear polynomial. This setup should assist learners in understanding how piecewise functions can combine different forms and how their domains are partitioned.
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