Widget Sales Jesaki Inc. is trying to enter the widget market. The research department established the following price-demand, cost, and revenue functions: p(x) = 60 - 1.20x Price- demand function Cost function Revenue function C(x) = 210 + 12x R(x) = xp(x) = x(60 - 1.20x)| where x is in thousands of widgets and C(x) and R(x) are in thousands of dollars. The price p(x) is the price in dollars of one widget when the demand is a thousand widgets. All three functions have domain 1 ≤ x ≤ 50.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Widget Sales
Jesaki Inc. is trying to enter the widget market. The research department
established the following price-demand, cost, and revenue functions:
p(x) = 60 1.20x
Price-
demand
function
Cost
function
C(x) = 210 + 12x
R(x) = xp(x) = x(60 - 1.20x)
where x is in thousands of widgets and C(x) and R(x) are in thousands
of dollars. The price p(x) is the price in dollars of one widget when the
demand is a thousand widgets. All three functions have domain
1 ≤ x ≤ 50.
Revenue
function
Transcribed Image Text:Widget Sales Jesaki Inc. is trying to enter the widget market. The research department established the following price-demand, cost, and revenue functions: p(x) = 60 1.20x Price- demand function Cost function C(x) = 210 + 12x R(x) = xp(x) = x(60 - 1.20x) where x is in thousands of widgets and C(x) and R(x) are in thousands of dollars. The price p(x) is the price in dollars of one widget when the demand is a thousand widgets. All three functions have domain 1 ≤ x ≤ 50. Revenue function
Use the Sales information above to answer this question.
What is the largest number of widgets that can be produced and sold for
Jesaki Inc. to break even?
widgets. Round to the nearest widget.
Transcribed Image Text:Use the Sales information above to answer this question. What is the largest number of widgets that can be produced and sold for Jesaki Inc. to break even? widgets. Round to the nearest widget.
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