(2x + 4) + 1 dx- x² + 4x + 5 x² + 2x– 10 2 (2x + 4) + 1 2 Consider dx = x2 (x² + 4x + 5) dx. evaluate - - x2 x² + 4x + 5, x2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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x2 + 2x- 10
(2x + 4) +1
x2 + 4x +5)
2
2
2
(2х+ 4) +1
Consider
dx - evaluate
-
-
x2 (x2 + 4x + 5)
x2
x2
x2 + 4x +5
2
2lnx
– In(x2 + 4x +5) – Arctan(x + 2) +C
2
– In(x2 + 4x + 5) + Arctan(x + 2) +C
2lnx
2
- In(x2 + 4x + 5) + Arctan(x + 2) + C
2lnx +
-
X
2
- In(x2 + 4x +5) - Arctan(x + 2) + C
2lnx +
-
Transcribed Image Text:x2 + 2x- 10 (2x + 4) +1 x2 + 4x +5) 2 2 2 (2х+ 4) +1 Consider dx - evaluate - - x2 (x2 + 4x + 5) x2 x2 x2 + 4x +5 2 2lnx – In(x2 + 4x +5) – Arctan(x + 2) +C 2 – In(x2 + 4x + 5) + Arctan(x + 2) +C 2lnx 2 - In(x2 + 4x + 5) + Arctan(x + 2) + C 2lnx + - X 2 - In(x2 + 4x +5) - Arctan(x + 2) + C 2lnx + -
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